Independent random samples from two regions in the same area gave the following chemical measurements (ppm). Assume the population distributions of the chemical are mound-shaped and symmetric for these two regions. Region I: *1; n=12 438 1013 1127 737 491 840 306 402 1155 1075 500 340 Region II: X2; n2=16 778 464 563 610 827 894 476 394 824 387 816 767 479 710 389 826 Let #1 be the population mean for 1 and 42 be the population mean for *2. Find a 90% confidence interval for H1-42. Question 5 options: -119.75 to 248.25

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Independent random samples from two regions in the same area gave the following chemical
measurements (ppm). Assume the population distributions of the chemical are mound-shaped
and symmetric for these two regions.
Region I: *1; n1=12
438 1013 1127 737 491 840 306 402 1155 1075 500 340
Region II: *2; n2 =16
778 464 563 610 827 894 476 394 824 387 816 767 479 710 389 826
Let Pi be the population mean for X1 and 42 be the population mean for 2. Find a 90%
confidence interval for #1-42.
Question 5 options:
-119.75 to 248.25
114.49 to 242.99
-253.50 to 125.00
-248.25 to 119.75
-125.00 to 253.50
Transcribed Image Text:Independent random samples from two regions in the same area gave the following chemical measurements (ppm). Assume the population distributions of the chemical are mound-shaped and symmetric for these two regions. Region I: *1; n1=12 438 1013 1127 737 491 840 306 402 1155 1075 500 340 Region II: *2; n2 =16 778 464 563 610 827 894 476 394 824 387 816 767 479 710 389 826 Let Pi be the population mean for X1 and 42 be the population mean for 2. Find a 90% confidence interval for #1-42. Question 5 options: -119.75 to 248.25 114.49 to 242.99 -253.50 to 125.00 -248.25 to 119.75 -125.00 to 253.50
Expert Solution
Step 1

Given Information:

Sample size (n1) = 12

Sample size (n2) = 16

Sample mean is obtained using the formula:

x¯1=ixn

Sample mean of first sample is:

x¯1=438+1013+....34012=702

Sample mean of second sample is:

x¯2=778+464+....82616=637.75

 

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