Find the minimum sample size n needed to estimate u for the given values of c, o, and E. c = 0.90, o = 9.8, and E = 1 Assume that a preliminary sample has at least 30 members. n = (Round up to the nearest whole number.)

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### Determining Sample Size

#### Problem Description:
Find the minimum sample size \( n \) needed to estimate \( \mu \) for the given values of \( c \), \( \sigma \), and \( E \).

Given values:
- \( c = 0.90 \)
- \( \sigma = 9.8 \)
- \( E = 1 \)

#### Additional Information:
Assume that a preliminary sample has at least 30 members.

#### Task:
Compute the value of \( n \) using the provided parameters and round up to the nearest whole number. 

#### Solution:
To solve this, apply the sample size formula for estimating the mean with a given confidence level:

\[ n = \left( \frac{Z_{\alpha/2} \cdot \sigma}{E} \right)^2 \]

Where:
- \( Z_{\alpha/2} \) is the critical value of the standard normal distribution corresponding to the desired confidence level \( c \).
- \( \sigma \) is the population standard deviation.
- \( E \) is the margin of error.

By calculating the critical value and inserting the known values into the formula, you can determine \( n \). Be sure to round the resulting value to the nearest whole number as specified.

**To proceed with the specific calculation:**
1. Determine the critical value \( Z_{\alpha/2} \) for \( c = 0.90 \).
2. Substitute these values into the formula.
3. Calculate and round the final value of \( n \).

This process yields the required sample size necessary to estimate the population mean \( \mu \) within the specified margin of error \( E \) at the given confidence level \( c \) and standard deviation \( \sigma \).

Please, fill in the required calculations and determine the value for \( n \).

**Interactive Component:**
\[ n = \boxed{} \] 

(Round up to the nearest whole number.)
Transcribed Image Text:### Determining Sample Size #### Problem Description: Find the minimum sample size \( n \) needed to estimate \( \mu \) for the given values of \( c \), \( \sigma \), and \( E \). Given values: - \( c = 0.90 \) - \( \sigma = 9.8 \) - \( E = 1 \) #### Additional Information: Assume that a preliminary sample has at least 30 members. #### Task: Compute the value of \( n \) using the provided parameters and round up to the nearest whole number. #### Solution: To solve this, apply the sample size formula for estimating the mean with a given confidence level: \[ n = \left( \frac{Z_{\alpha/2} \cdot \sigma}{E} \right)^2 \] Where: - \( Z_{\alpha/2} \) is the critical value of the standard normal distribution corresponding to the desired confidence level \( c \). - \( \sigma \) is the population standard deviation. - \( E \) is the margin of error. By calculating the critical value and inserting the known values into the formula, you can determine \( n \). Be sure to round the resulting value to the nearest whole number as specified. **To proceed with the specific calculation:** 1. Determine the critical value \( Z_{\alpha/2} \) for \( c = 0.90 \). 2. Substitute these values into the formula. 3. Calculate and round the final value of \( n \). This process yields the required sample size necessary to estimate the population mean \( \mu \) within the specified margin of error \( E \) at the given confidence level \( c \) and standard deviation \( \sigma \). Please, fill in the required calculations and determine the value for \( n \). **Interactive Component:** \[ n = \boxed{} \] (Round up to the nearest whole number.)
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