Find the minimum sample size n needed to estimate u for the given values of c, o, and E c = 0.90, o = 9.1, and E= 1 Assume that a preliminary sample has at least 30 members. %3D (Round up to the nearest whole number.)
Find the minimum sample size n needed to estimate u for the given values of c, o, and E c = 0.90, o = 9.1, and E= 1 Assume that a preliminary sample has at least 30 members. %3D (Round up to the nearest whole number.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Example Problem: Determining Minimum Sample Size**
**Objective:** Find the minimum sample size \( n \) needed to estimate the population mean (\( \mu \)) given specific confidence level and error margins.
**Given:**
- Confidence level (\( c \)): 0.90
- Population standard deviation (\( \sigma \)): 9.1
- Margin of error (\( E \)): 1
**Instructions:** Assume a preliminary sample has at least 30 members.
**Solution Formula:**
The formula to calculate the minimum sample size needed is:
\[
n = \left( \frac{Z \cdot \sigma}{E} \right)^2
\]
- **Confidence Level (\( c \))**: This represents the degree of certainty that the true parameter (\( \mu \)) lies within the specified interval. A typical \( Z \)-value for \( c = 0.90 \) can be found using a standard normal distribution table.
- **\( \sigma \)**: The population standard deviation.
- **\( E \)**: The desired margin of error, which indicates the maximum acceptable difference between the sample estimate and the true population parameter.
**Calculate and Round:**
After using the above formula and calculating, remember to round up to the nearest whole number.
**Calculation Process:**
1. Determine the \( Z \)-value for \( c = 0.90 \).
2. Substitute \( Z \), \( \sigma = 9.1 \), and \( E = 1 \) into the formula.
3. Calculate \( n \).
4. Round \( n \) to the nearest whole number.
**Output:**
Fill in the calculated \( n \) as follows:
\[ n = \Box \] (Round up to the nearest whole number.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff840fd16-304a-4687-bc6a-eb295e8e37a9%2F0ba6ede8-adde-4aff-805c-91a75f392ba4%2F2cgi6o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Example Problem: Determining Minimum Sample Size**
**Objective:** Find the minimum sample size \( n \) needed to estimate the population mean (\( \mu \)) given specific confidence level and error margins.
**Given:**
- Confidence level (\( c \)): 0.90
- Population standard deviation (\( \sigma \)): 9.1
- Margin of error (\( E \)): 1
**Instructions:** Assume a preliminary sample has at least 30 members.
**Solution Formula:**
The formula to calculate the minimum sample size needed is:
\[
n = \left( \frac{Z \cdot \sigma}{E} \right)^2
\]
- **Confidence Level (\( c \))**: This represents the degree of certainty that the true parameter (\( \mu \)) lies within the specified interval. A typical \( Z \)-value for \( c = 0.90 \) can be found using a standard normal distribution table.
- **\( \sigma \)**: The population standard deviation.
- **\( E \)**: The desired margin of error, which indicates the maximum acceptable difference between the sample estimate and the true population parameter.
**Calculate and Round:**
After using the above formula and calculating, remember to round up to the nearest whole number.
**Calculation Process:**
1. Determine the \( Z \)-value for \( c = 0.90 \).
2. Substitute \( Z \), \( \sigma = 9.1 \), and \( E = 1 \) into the formula.
3. Calculate \( n \).
4. Round \( n \) to the nearest whole number.
**Output:**
Fill in the calculated \( n \) as follows:
\[ n = \Box \] (Round up to the nearest whole number.)
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