Find the minimum sample size n needed to estimate u for the given values of c, o, and E c = 0.90, o = 9.1, and E= 1 Assume that a preliminary sample has at least 30 members. %3D (Round up to the nearest whole number.)

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**Example Problem: Determining Minimum Sample Size**

**Objective:** Find the minimum sample size \( n \) needed to estimate the population mean (\( \mu \)) given specific confidence level and error margins.

**Given:**
- Confidence level (\( c \)): 0.90
- Population standard deviation (\( \sigma \)): 9.1
- Margin of error (\( E \)): 1

**Instructions:** Assume a preliminary sample has at least 30 members.

**Solution Formula:**
The formula to calculate the minimum sample size needed is:

\[
n = \left( \frac{Z \cdot \sigma}{E} \right)^2
\]

- **Confidence Level (\( c \))**: This represents the degree of certainty that the true parameter (\( \mu \)) lies within the specified interval. A typical \( Z \)-value for \( c = 0.90 \) can be found using a standard normal distribution table.

- **\( \sigma \)**: The population standard deviation.

- **\( E \)**: The desired margin of error, which indicates the maximum acceptable difference between the sample estimate and the true population parameter.

**Calculate and Round:**
After using the above formula and calculating, remember to round up to the nearest whole number.

**Calculation Process:**

1. Determine the \( Z \)-value for \( c = 0.90 \).
2. Substitute \( Z \), \( \sigma = 9.1 \), and \( E = 1 \) into the formula.
3. Calculate \( n \).
4. Round \( n \) to the nearest whole number.

**Output:**
Fill in the calculated \( n \) as follows:

\[ n = \Box \] (Round up to the nearest whole number.)
Transcribed Image Text:**Example Problem: Determining Minimum Sample Size** **Objective:** Find the minimum sample size \( n \) needed to estimate the population mean (\( \mu \)) given specific confidence level and error margins. **Given:** - Confidence level (\( c \)): 0.90 - Population standard deviation (\( \sigma \)): 9.1 - Margin of error (\( E \)): 1 **Instructions:** Assume a preliminary sample has at least 30 members. **Solution Formula:** The formula to calculate the minimum sample size needed is: \[ n = \left( \frac{Z \cdot \sigma}{E} \right)^2 \] - **Confidence Level (\( c \))**: This represents the degree of certainty that the true parameter (\( \mu \)) lies within the specified interval. A typical \( Z \)-value for \( c = 0.90 \) can be found using a standard normal distribution table. - **\( \sigma \)**: The population standard deviation. - **\( E \)**: The desired margin of error, which indicates the maximum acceptable difference between the sample estimate and the true population parameter. **Calculate and Round:** After using the above formula and calculating, remember to round up to the nearest whole number. **Calculation Process:** 1. Determine the \( Z \)-value for \( c = 0.90 \). 2. Substitute \( Z \), \( \sigma = 9.1 \), and \( E = 1 \) into the formula. 3. Calculate \( n \). 4. Round \( n \) to the nearest whole number. **Output:** Fill in the calculated \( n \) as follows: \[ n = \Box \] (Round up to the nearest whole number.)
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