Find the mechanical energy of a block-spring system having a spring constant of 1.3 N/cm and an oscillation amplitude of 2.5 cm. Don't forget to convert units
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Find the mechanical energy of a block-spring system having a spring constant of 1.3 N/cm and an oscillation amplitude of 2.5 cm. Don't forget to convert units.
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- A 0.300 kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 120.0 The block is pulled from equilibrium position at x = 0.000 m to a displacement x = + 0.080m and is released from rest. The block then executes simple harmonic motion along the horizontal x axis. What the total mechanical energy of the system ? Give your answer in Sl units .how to do?A 60.0-g object connected to a spring with a force constant of 40.0 N/m oscillates with an amplitude of 5.00 cm on a frictionless, horizontal surface. (a) Find the total energy of the system.(b) Find the speed of the object when its position is 1.30 cm. (Let 0 cm be the position of equilibrium.)(c) Find the kinetic energy when its position is 3.50 cm.(d) Find the potential energy when its position is 3.50 cm.
- AsapA spring hangs vertically from a ceiling. The spring constant of the spring is k=15 N/m. A 2kg object has been attached to the spring and the spring has already come to its new equilibrium. Someone pulls the object down by 5cm and releases it at time t = 0s. The spring and object begin to oscillate under simple harmonic motion. Find the total energy of the system, the maximum kinetic energy, the maximum potential energy, and the positions where the maximum energies occur. Answers: 0.01875 J, 0.01875 JA simple pendulum with a length of 1.73 m and a mass of 6.74 kg is given an initial speed of 2.36 m/s at its equilibrium position. (a) Assuming it undergoes simple harmonic motion, determine its period (in s). (b) Determine its total energy (in J). (c) Determine its maximum angular displacement (in degrees). (For large v, and/or small /, the small angle approximation may not be good enough here.) (d) What If? Based on your answer to part (c), by what factor would the total energy of the pendulum have to be reduced for its motion to be described as simple harmonic motion using the small angle approximation where 0 ≤ 10°?
- An apple weighs 1.04 NN. When you hang it from the end of a long spring of force constant 1.54 N/mN/m and negligible mass, it bounces up and down in SHM. If you stop the bouncing and let the apple swing from side to side through a small angle, the frequency of this simple pendulum is half the bounce frequency. (Because the angle is small, the back and forth swings do not cause any appreciable change in the length of the spring.) What is the unstretched length of the spring (i.e., without the apple attached)? Express your answer with the appropriate units.You attach one end of a spring with a force constant k = 913 N/m to a wall and the other end to a mass m = 2.62 kg and set the mass-spring system into oscillation on a horizontal frictionless surface as shown in the figure. To put the system into oscillation, you pull the block to a position x₁ = 4.76 cm from equilibrium and release it. (a) Determine the potential energy stored in the spring before the block is released. (b) Determine the speed of the block as it passes through the equilibrium position. m/s (c) Determine the speed of the block when it is at a position x/4. m/sA 50.0 cm long spring with spring constant 224 N/m has a mass 1.4 kg attached to it, and it can oscillate on a horizontal table without any friction. The spring is pulled by a distance 7 cm from the resting position and released. What is the kinetic energy (in joules) of the mass at the instant when the length of the spring is 51 cm. Ans: 0.5376