A 2.8 kg block is set on a horizontal table. One end of a spring is attached to the block, and the other end is attcahed to a fixed support. The block is pulled back 30 cm from the spring's equilibrium position and released such that it oscillated horizontally. At the quillibrium position, the velocity of the block is 3.2 m/s. What is the spring constant of the spring? Assume a frictionless table and a massless spring. _______ N/m

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Chapter1: Units, Trigonometry. And Vectors
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A 2.8 kg block is set on a horizontal table. One end of a spring is attached to the block, and the other end is attcahed to a fixed support. The block is pulled back 30 cm from the spring's equilibrium position and released such that it oscillated horizontally. At the quillibrium position, the velocity of the block is 3.2 m/s. What is the spring constant of the spring? Assume a frictionless table and a massless spring. 

_______ N/m

Expert Solution
Step 1

When block is released ,it will execute S.H.M.  with Max elongation,A = 30 cm = 0.30 m .

Mass of the block m= 2.8 kg .

Let spring constant of the spring be k .

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