A 2.8 kg block is set on a horizontal table. One end of a spring is attached to the block, and the other end is attcahed to a fixed support. The block is pulled back 30 cm from the spring's equilibrium position and released such that it oscillated horizontally. At the quillibrium position, the velocity of the block is 3.2 m/s. What is the spring constant of the spring? Assume a frictionless table and a massless spring. _______ N/m

Q: A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless…

A: mass = 0.1 kg x = 0.15 m K = 90 N/m initial potential energy = 101.25 J angular frequency = 30…

Q: A 17.2-kg mass is attached to a horizontal frictionless spring. The system has a spring with a…

A:

Q: h one end of a spring with a force constant k = 753 N/m to a wall and the other end to a mass  m =…

A: Givenk=753 N/mm=1.42 kgxi=6.56 cm=0.0656 m

Q: An m=20.0g object is held against the free end of a spring of constant k=25.0N/m that is compressed…

A: The time period of the object fall from the 1 m off the table Substitute all values in the above…

Q: One type of BB gun uses a spring-driven plunger to blow the BB from its barrel. (a) Calculate the…

A: Approach to solving the question:Please see attached photos for detailed solutions. Thank you.…

Q: 3. A box (mass = 100 g) is initially connected to a compressed (x = 80 cm) spring (k = 100 N/m) at…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: A horizontal spring system consists of a block of mass 3.50 kg on a frictionless surface attached to…

A: (a) From Hooke’s law, the magnitude of the spring force acting on the block is given as, Here, k…

Q: A spring-loaded pellet gun is designed to fire 3.20 g projectiles horizontally at a speed of 42.8…

A: The given data are: m=3.20 g=3.20×10-3 kgv=42.8 m/sx=8.60 cm=8.60×10-2 m

Q: An object slides on a rough horizontal surface. It is attached to one end of a horizontal spring…

A: Solution: m = 1 kg k = 350 N/m v = 3.3 m/s x = 0.7 m

Q: As shown in the figure below, a box of mass m = 8.00 kg is sliding across a horizontal frictionless…

A:

Q: The spring in a spring gun has a force constant k = 600. N/m. It is compressed 2.5 cm from its…

A: we can use the principle of conservation of energy to find the speed of ball . The potential energy…

Q: A 450 g block lies on a frictionless surface. It is pushed against a spring with spring constant 2.5…

A: As the block is released from point A, the elastic potential energy of the spring is transferred to…

Q: An ideal spring hangs from the ceiling. A 1.55 kg mass is hung from the spring, stretching the…

A: Solution:At equlllibrium position, we have:mg = kdwhere, m is mass             g is acceleration due…

Q: A 0.42-kg block is attached to the end of a horizontal ideal spring and rests on a frictionless…

A: When the block is pulled, the force experienced due to stretching of the spring is Fs=-kx The force…

Q: A horizontal spring is attached to a wall at one end and a mass of 5.3 kg on the other end. The…

A:

Q: A 5 kg object is attached to a spring and is oscillating on a horizontal surface. When the object…

A:

Q: A block of mass m=0.679kg is fastened to an unstrained horizontal spring whose spring constant is…

A:

Q: An object oscillates on a spring. When it's displacement from equilibrium is 3.00 cm, the object has…

A: Write the expression for conservation of energy .

Q: A 1.00 kg object is attached to a horizontal spring. The spring is initially stretched by 0.200 m,…

A:

Q: (d) What is the speed of the block when its displacement is 0.160 m? m/s (e) Find the kinetic energy…

A: Note :- Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the…

Q: A 0.60 kg object rests on a frictionless horizontal surface, where it is attached to a massless…

A: Mass of object = 0.6 kg  Spring constant = 20.5 N/m  Position of object when the spring has been…

Q: A 2.30 kg cube rests upon a frictionless, horizontal floor. The cube is attached to a horizontal…

A: Mass of cube (m) = 2.30 kgForce constant of the spring (k) = 430 N/mInitial displacement of the mass…

Q: A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.10 N is…

A:

Q: A 2.30 kg cube rests upon a frictionless, horizontal floor. The cube is attached to a horizontal…

A:

Q: A 0.72 kg mass is held against the a compressed spring and released from rest. The linear spring is…

A: Some portion of strain energy stored in the spring will be converted in to kinetic energy of the…

Q: An elastic cord is 74 cmcm long when a weight of 72 NN hangs from it but is 80 cmcm long when a…

A: Given data: Initial length (x1) = 74 cm = 0.74 m Initial force (F1) = 72 N Final length (x2) = 80 cm…

Q: A block weighing 10.0 N is attached to the lower end of a vertical spring (k =200.0 N/m), the other…

A:

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 590 N/m as shown in the…

A: The energy stored in spring will be transformed into the kinetic energy of the block when it reaches…

Q: A 240 gg air-track glider is attached to a spring. The glider is pushed in 11.2 cmcm against the…

A:

Q: When a horizontal spring is extended 5.60cm from equilibrium it exerts a restoring force of 2.50N .…

A:

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.