A 127 kg block is released at height h = 4.4 m as shown. The track is frictionless except for a portion of length 7.1 m. The block travels down the track, hits a spring of force constant k = 1779 N/m, and compresses it 1.6 m from its equilibrium position before coming to rest momentarily. The acceleration of gravity is 9.8 m/s². 127 kg 4.4 m ↓ fl 1779 N/m 1000000004 业不 7.1 m Determine the coefficient of kinetic friction between surface and block over the 7.1 m track length. 1.6 m

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Chapter1: Units, Trigonometry. And Vectors
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A 127 kg block is released at height h =
4.4 m as shown. The track is frictionless
except for a portion of length 7.1 m. The
block travels down the track, hits a spring of
force constant k = 1779 N/m, and compresses
it 1.6 m from its equilibrium position before
coming to rest momentarily.
The acceleration of gravity is 9.8 m/s².
127 kg
4.4 m
↓
1779 N/m
1000000004
→ K
7.1 m
Determine the coefficient of kinetic friction
between surface and block over the 7.1 m
track length.
1.6 m
Transcribed Image Text:A 127 kg block is released at height h = 4.4 m as shown. The track is frictionless except for a portion of length 7.1 m. The block travels down the track, hits a spring of force constant k = 1779 N/m, and compresses it 1.6 m from its equilibrium position before coming to rest momentarily. The acceleration of gravity is 9.8 m/s². 127 kg 4.4 m ↓ 1779 N/m 1000000004 → K 7.1 m Determine the coefficient of kinetic friction between surface and block over the 7.1 m track length. 1.6 m
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