Find the Icm for this shape. Hollow Sphere M=40 kg Rod M=100 kg L=16 m %3D R=5 m %3D 4642.38 kg.m^2 4594.32 kg.m^2 4665.12 kg.m^2 4628.57 kg.m^2 4571.85 kg.m^2

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Chapter1: Units, Trigonometry. And Vectors
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Find the Moment of Inertia from the center of mass of the following object.

Find the Icm for this shape.
Hollow Sphere
M=40 kg
R=5 m
Rod
M=100 kg
L=16 m
%3D
4642.38 kg.m^2
4594.32 kg.m^2
4665.12 kg.m^2
4628.57 kg.m^2
O 4571.85 kg.m^2
Transcribed Image Text:Find the Icm for this shape. Hollow Sphere M=40 kg R=5 m Rod M=100 kg L=16 m %3D 4642.38 kg.m^2 4594.32 kg.m^2 4665.12 kg.m^2 4628.57 kg.m^2 O 4571.85 kg.m^2
Expert Solution
Step 1

First we find the position of the center of mass

take the far end of rod (right end) as origin

                                                       rcmm1r1+m1r2m1+m2

r1=16 m   m1=40 kg (center of mass of hollow sphere is at the center of sphere)

r2=8 m   m2=100 kg  (center of mass of rod is at midpoint)

rcm=1440/140= 10.285m 

 

Step 2

Inertia of hollow sphere= 23MR2+ M(16-10.285)2    

here M=40 kg

R= 5 m

                                      = 1973.115 kg m2

Inertia of rod=   ML212+M(10.285-8)2

M= 100 kg

L=16 m

                     =  2655.455 kgm2

 

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