(a) Calculate the angular momentum, in kg- m²/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.450 kg- m². kg-m²/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia, in kg m², if his angular velocity drops to 2.15 rev/s. kg-m² (c) Suppose instead he keeps his arms in and allows friction with the ice to slow him to 3.00 rev/s. What average torque, in N m, was exerted if this takes 19.0 seconds? (Indicate the direction with the sign of your answer. Assume that the skater's rotation is in the positive direction.) N-m

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(b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia, in kg-m², if his
angular velocity drops to 2.15 rev/s.
1.256
✓kg-m²
(c) Suppose instead he keeps his arms in and allows friction with the ice to slow him to 3.00 nev/s. What average torque, in N m, was exerted if this takes 19.0 seconds?
(Indicate the direction with the sign of your answer. Assume that the skater's rotation is in the positive direction.)
0.445
X N·m
Transcribed Image Text:(b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia, in kg-m², if his angular velocity drops to 2.15 rev/s. 1.256 ✓kg-m² (c) Suppose instead he keeps his arms in and allows friction with the ice to slow him to 3.00 nev/s. What average torque, in N m, was exerted if this takes 19.0 seconds? (Indicate the direction with the sign of your answer. Assume that the skater's rotation is in the positive direction.) 0.445 X N·m
(a) Calculate the angular momentum, in kg m²/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.450 kg. m².
kg-m²/s
(b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia, in kg m², if his
angular velocity drops to 2.15 rev/s.
kg-m2
(c) Suppose instead he keeps his arms in and allows friction with the ice to slow him to 3.00 rev/s. What average torque, in N m, was exerted if this takes 19.0 seconds?
(Indicate the direction with the sign of your answer. Assume that the skater's rotation is in the positive direction.)
N-m
Transcribed Image Text:(a) Calculate the angular momentum, in kg m²/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.450 kg. m². kg-m²/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia, in kg m², if his angular velocity drops to 2.15 rev/s. kg-m2 (c) Suppose instead he keeps his arms in and allows friction with the ice to slow him to 3.00 rev/s. What average torque, in N m, was exerted if this takes 19.0 seconds? (Indicate the direction with the sign of your answer. Assume that the skater's rotation is in the positive direction.) N-m
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