Find the energy released when 21¹ Pb undergoes - decay to become 21¹Bi. Be sure to take into account the mass of the electrons associated with the neutral atoms. 83
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- 190, which has an atomic mass of 19.003577 u, decays via p decay to 19F, which has an atomic mass of 18.998403 u. How much energy is released in this decay process? (This energy goes to the kinetic energy of the electron and the antineutrino.)214Po undergoes alpha decay to become 210Pb. If the Q value of the reaction is 7.83 MeV, calculate the kinetic energy of the alpha particle released.The ceramic glaze on a red-orange Fiestaware plate is U2O3 and contains 50.0 grams of 238U , but very little 235U. Calculate the total energy that will be released by the 238U decay.
- 1) Complete the following nuclear fission reaction of thorium-232. 232Th + n → 99Kr + 124Xe + ? a) 4He b) 10B c) 10n d) 11n e) 11B 2) Calculate the energy released in the reaction. The atomic masses are 232Th = 232.038051 u, 99Kr = 98.957606 u, and 124Xe = 123.905894 u. (Express your answer to five significant figures).Answers to d and e pleaseComplete the following nuclear reactions:
- Help me to solve this proplemsA sample of wood from an archaeological excavation is dated by using a mass spectrometer to measure the fraction of 14C atoms. Suppose 100 atoms of 14C are found for every 1.0 * 1015 atoms of 12C in the sample. What is the wood’s age?Glow-in-the-dark signs take advantage of β− particles emitted in the decay of certain isotopes that glow when interacting with matter. If such a sign has an activity of 14.7 Ci when it's manufactured and contain isotopes with a half-life of 13.3 y, what will its activity in Ci be 3.9 y later?
- Please answer this within 30 mins ! I will upvote !Find the mass energy released in the alpha decay of Ac-220. atomic mass of 220 Ac = 220.014763 u; 89 atomic mass of 216 Fr = 216.003198 u; 87 atomic mass of He = 4.002603 u; u = 931.5 MeV/c^2. (in MeV) OA: 0.898 OB: 1.302 OC: 1.888 OD: 2.738 OE: 3.971 OF: 5.757 OG: 8.348 OH: 12.1051) Complete the reaction: 242Am + ? n → 90Sr + 149La + 4n a) n b) 2n c) 3n d) 4n e) 5n 2) Calculate the energy (in MeV) released in the nuclear fission reaction. The atomic masses are 242Am = 242.059549 u, 90Sr = 89.9077387 u, and 149La = 148.934733 u. (Express your answer to six significant figures).