Find the electric potential at x=0.700m. Express your answer to three significant figures and include appropriate units. Find the value of x between 0 and 1.00 m where the electric potential is zero. Express your answer to three significant figures and include appropriate units.
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In (Figure 1), the charge q=4.03×10^−9C
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- 13A From Equation 25.6, we have the following. AV = -Ed = -(7.2 × 104 v/m)(0.60 m) = B V From Equation 25.3, we have the following. AU = qAV = eAV = (1.6 x 10-19 C)(AV) | The negative sign means that the potential energy of the system decreases as the proton moves in the direction of the electric field. This decrease is consistent with the conservation of energy in an isolated system: as the proton accelerates in the direction of the field, it gains kinetic energy and at the same time the system loses electric potential energy. The increase in kinetic energy of a charged particle in an electric field is exploited in many devices, including electron guns for TV picture tubes and particle accelerators for research in particle physics. You can predict and observe the speed of the proton as it arrives at the negative plate for random values of the electric field using this Interactive Example. Hints: Getting Started | I'm Stuck Exercise 25.2 For the previous example, apply the principle of…A parallel-plate capacitor is constructed with circular plates of radius 5.10x10-2 m . The plates are separated by 0.20 mm , and the space between the plates is filled with a dielectric with dielectric constant K. When the charge on the capacitor is 1.4 µC the potential difference between the plates is 1030 V. Part A ▼ Find the value of the dielectric constant, K. Express your answer using two significant figures. ν Αφ K = Submit Request Answer Provide Feedback
- The electric potential at the dot in the figure is 3140 V. (Figure 1) You may want to review (Pages 705-706). Figure 4.0 cm 5.0 nC 2.0 cm ▼ Part A What is charge q? Express your answer to two significant figures and include the appropriate units. q= Value Submit μÅ Provide Feedback Request Answer Units ?In the figure below(Figure 1), each capacitor has C=3.80 μF and Vab=24.0V. (a) Calculate the charge on each capacitor. (b) Calculate the potential difference across each capacitor.The electric potential difference AV, also called voltage, is expressed in terms of the electric field as follows AV = Edr where, a is the initial position and b is the final position. If an electric field in a region in space is defined as E = Br² where B is just a constant without an arbitrary value. What is the electric potential difference from position 0 to R? 1 AV = Br? AV = -Br 1 AV = BR3 AV = O AV = (1– BR²)aR 1 AV = Br 1 AV = BR3 Ο ΔV- (1-β)αR3 O AV = - BR3 ΔV= -글(1-B)
- Please asapWhat is the magnitude of the electric field at the point (2.90 i-7.20 j+5.50 k) m if the electric potential is given by V = 5.30xyz², where Vis in volts and x, y, and z are in meters? Number i UnitsIn the figure, the charge q=0.880×10^−9C. A) Find the electric potential at x=0.450m Express your answer using appropriate units. B) Find the value of x between 0 and 1.00 m where the electric potential is zero. Express your answer using appropriate units.
- A moving particle encounters an external electric field that decreases its kinetic energy from 9040 eV to 6590 eV as the particle moves from position A to position B. The electric potential at A is -55.0 V, and that at B is +15.0 V. Determine the charge of the particle. Include the algebraic sign (+ or -) with your answer. Lower potential A Higher potential VBThe electric potential in a region of space is V = Part A E= Submit What is the strength of the electric field at (x, y) = (2.7 m, 2.8 m)? Express your answer using two significant figures. Part B 0= 2 of 15 || ΑΣΦ 4 → C Request Answer 15. ΑΣΦ Submit (300 V-m) √x² + y² 2 Request Answer What is the direction of the electric field at (x, y) = (2.7 m, 2.8 m)? Give the direction as an angle ccw from the positive x-axis. Express your answer in degrees using two significant figures. BALAD where and y are in meters. ? V/m ccw from the positive z-axisAn electron moving parallel to the x axis has an initial speed of 3.7 x 106 m/s at the origin. Its speed is reduced to 1.4 x 105 m/s at x = 2 cm. Calculate the electric potential difference 1. between the origin and x -= 2 cm. 2. A proton is released from rest in a uniform electric field whose magnitude is 5000 V/m. Through what potential difference will it have passed after moving 0.25 meters? How fast will it be going after it has travelled 0.25 meters?