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Find the distance between the two charges, q1 with 36 nC and q2 with 22 nC. The Electric Potential Energy is 9.912 × 10-³ N·m Find the value of Charge qo if its electric field has a value of 8.41 x 10-³ N/C and a Force Fo of 1.3 N What is the Voltage of the appliance if its fuse rating is 10A and its power is 990 W Using eq. 2 for Coulomb's law, solve for the Force of 2 charges, q₁ = -200 nC and 92 = +193 nC with a distance of 10.3 cm. (Note: € has a value of 8.85 x 10-¹² F/m) (F= Nm/C²) Find the value of current if the loop has 56 µ2 and 10 V

Find the distance between the two charges, q1 with 36 nC and q2 with 22 nC. The Electric Potential Energy is 9.912 × 10-³ N·m Find the value of Charge qo if its electric field has a value of 8.41 x 10-³ N/C and a Force Fo of 1.3 N What is the Voltage of the appliance if its fuse rating is 10A and its power is 990 W Using eq. 2 for Coulomb's law, solve for the Force of 2 charges, q₁ = -200 nC and 92 = +193 nC with a distance of 10.3 cm. (Note: € has a value of 8.85 x 10-¹² F/m) (F= Nm/C²) Find the value of current if the loop has 56 µ2 and 10 V

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Ohm's Law The relationship among voltage, current, and resistance is summarized by a statement called Ohm's law. George Simon Ohm discovered that the current in a circuit is directly proportional to the voltage established across the circuit and is inversely proportional to the resistance of the circuit. In short, Current (1) = Voltage (V) Resistance (R) Or in units form: Amperes (A)= Volts (V) Ohms Ω Current and voltage are proportional to each other for a given circuit of a constant resistance .It tells us that, to obtain twice as much of the original current, we must double its voltage. Increase in voltage means increase in current. On the other hand, if you double the resistance, the current will be half what it would be otherwise. The greater the resistance, the smaller the current. The lesser the resistance, the greater the current. Ohm's law states that 1 A is produced by 1 V of potential difference across a circuit that has 10 resistance. Example 1 Find the current I through a resistor of resistance R = 2 2 if the voltage across the resistor is 6 V. Given: R = 20 V=6 V Find I Solution: I = V/R I = 6V 20 I= 3A KEEP IN MIND! For a given potential difference, more resistance means less current. 7
Transcribed Image Text:Ohm's Law The relationship among voltage, current, and resistance is summarized by a statement called Ohm's law. George Simon Ohm discovered that the current in a circuit is directly proportional to the voltage established across the circuit and is inversely proportional to the resistance of the circuit. In short, Current (1) = Voltage (V) Resistance (R) Or in units form: Amperes (A)= Volts (V) Ohms Ω Current and voltage are proportional to each other for a given circuit of a constant resistance .It tells us that, to obtain twice as much of the original current, we must double its voltage. Increase in voltage means increase in current. On the other hand, if you double the resistance, the current will be half what it would be otherwise. The greater the resistance, the smaller the current. The lesser the resistance, the greater the current. Ohm's law states that 1 A is produced by 1 V of potential difference across a circuit that has 10 resistance. Example 1 Find the current I through a resistor of resistance R = 2 2 if the voltage across the resistor is 6 V. Given: R = 20 V=6 V Find I Solution: I = V/R I = 6V 20 I= 3A KEEP IN MIND! For a given potential difference, more resistance means less current. 7
1. Find the distance between the two charges, q1 with 36 nC and q2 with 22 nC. The Electric Potential Energy is 9.912 x 10-³ N·m 2. Find the value of Charge qo if its electric field has a value of 8.41 x 10-³ N/C and a Force Fo of 1.3 N 3. What is the Voltage of the appliance if its fuse rating is 10A and its power is 990 W 4. Using eq. 2 for Coulomb's law, solve for the Force of 2 charges, q₁ = -200 nC and 92 = +193 nC with a distance of 10.3 cm. (Note: co has a value of 8.85 x 10-¹2 F/m) (F= N m/ C²) 5. Find the value of current if the loop has 56 µ2 and 10 V
Transcribed Image Text:1. Find the distance between the two charges, q1 with 36 nC and q2 with 22 nC. The Electric Potential Energy is 9.912 x 10-³ N·m 2. Find the value of Charge qo if its electric field has a value of 8.41 x 10-³ N/C and a Force Fo of 1.3 N 3. What is the Voltage of the appliance if its fuse rating is 10A and its power is 990 W 4. Using eq. 2 for Coulomb's law, solve for the Force of 2 charges, q₁ = -200 nC and 92 = +193 nC with a distance of 10.3 cm. (Note: co has a value of 8.85 x 10-¹2 F/m) (F= N m/ C²) 5. Find the value of current if the loop has 56 µ2 and 10 V
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