Find the derivative. 8) y = (x + 1)2(x2 + 1)-3 A) - = 2(x+ 1)(x2 + 1)-4(2x2 - 3x - 1) B) Y =-2(x + 1)(x2 + 1)-4(2x2 + 3x - 1) dx C)= 2(x + 1)(x2+ 1)-4(2x2 + 3x – 1) =-2(x + 1)(x2 + 1)-4(2x2 - 3x - 1)
Find the derivative. 8) y = (x + 1)2(x2 + 1)-3 A) - = 2(x+ 1)(x2 + 1)-4(2x2 - 3x - 1) B) Y =-2(x + 1)(x2 + 1)-4(2x2 + 3x - 1) dx C)= 2(x + 1)(x2+ 1)-4(2x2 + 3x – 1) =-2(x + 1)(x2 + 1)-4(2x2 - 3x - 1)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:Find the derivative.
8) y= (x+ 1)2(x2 + 1)-3
A) = 2(x+ 1)(x2+ 1)-4(2x2 – 3x – 1)
B) Y --2(x + 1)(x2 + 1)-4(2x2 + 3x - 1)
%3D
%3D
=2(x+
1)(x2 + 1)-4(2x2 + 3x – 1)
D)--2(x + 1)(x2 + 1)-4(2x2 - 3x – 1)
dx
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