Find the currents I and 12 in the circuit shown Show all your calculations. R-0.52 www 26 V 12 V R₂-202 ничн In the circuit shown, the internal resistances of the two real batteries are r₁ = 1.0 2 and -r₁ = 2.0 2, while the resistance R is not known. If the power dissipated by ra is 4.5 W. determine the power being dissipated in R. E₁ = 23 V E₂- 13 V R R-12
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- The capacitor in the circuit shown below is initially uncharged. The switch is closed at t = 0 s. AV battery = 24 V, C = 3.0 μF, and R = 2.0 02. What is the current in the circuit at t = 9.0 µs, in Ampere? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1. R2, and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, variable, word, etc. All numerical answers should be in three significant figures. R| R2 R3 First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is milliamperes) Similarly the current across R2 is: 12= mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the currents across each resistor: 1=h+/2 +13 |= Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors…The parallel circuit at the right depicts two resistors connected to a voltage source. The voltage source (AVtot) is a 12-V source and the resistor values are 7.4 Q (R,) and 3.9 Q (R2). a. Determine the equivalent resistance of the circuit. [ Select ] b. Determine the current in each branch resistor: Current in R, = [Select] Current in R, = [Select ] %3D C. Determine the total current in the circuit. Select ]
- Consider the following circuit ww R1 R2 where V = 10.0V, R2= 10.0k2 and R3 = 20.0kN. 1. Are the resistors connected in series or parallel? 2. What is the equivalent resistance of the resistor pair. 3. Use V = IR and the equivalent resistance to find the total current though the battery. 4. How much current flows through each of the two original resistors? (Hint: Note that each of the two resistors has the same voltage across them so you can use ohms law for each of them.) 5. Sum the two currents together, do you get the current through the battery? wwIn the picture below there are 2 electromotive force with a large voltage of 12.5 V and an internal resistance of 0.75 Ohm arranged in series. Furthermore, the circuit with a series of resistance as shown in the picture. EJ & R₁=852 B R=1602 ·m R$40 R₂=1602 mmm. R₁=802 Calculate : a. The total resistance of the circuit. b. Strong current generated www.Find the expression for the equivalent resistance of 3 resistors (R1,R2,R3) connected in parallel. Sol. In a parallel connection, voltage drops across the resistors so:
- What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1, R2, and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, variable, word, etc. All numerical answers should be in three significant figures. R1 R2 R3 A First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) 4 = mA Similarly the current across R2 is: And the current across R3 is: The current read by the ammeter is the sum of the currents across each resistor: 1=h+l2+l3 mA Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in…Find the current I through the circuit.I= (mA). Find the voltage across each resistor. Give your answer as a comma-separated list in unit of volt, as an absolute value. potential drops across R1, R2, R3, R4, and R5 (in volt, in order): What is the power supplied by the batteries—that is, the power dissipated or consumed by the circuit?P= (W).Consider the following circuit R1 V R2 where V = 30V, R2 = 30 and R = 30. 1. Are the resistors connected in series or parallel? 2. What is the equivalent resistance of the resistor pair. 3. Use V = IR and the equivalent resistance to find the total current though the battery. %3D 4. How much current flows through each of the two original resistors? ww
- Please answer the last sub-part.In the circuit shown in the figure (Figure 1), the current in the 20.0-V battery is 5.00 A in the direction shown and the voltage across the 8.00-SN resistor is 18.0 V, with the lower end of the resistor at higher potential. Part D Find the direction of the current I through the 200.0-V battery. The current through the 200.0 V battery is in the direction from the - to the + terminal. The current through the 200.0 V battery is in the direction from the + to the - terminal. Request Answer Submit Figure < 1 of 1 Part E Find the resistance R. 20.0 N R 30.0 N VO AZ R ? 18.0 N 8.00 N R= 200.0 V- - 20.0 V Submit Request Answer 5.00 APart E Calculate the current through each resistor in the figure if each resistance R=1.38 kf and V 12.0 V .(Figure 1) Calculate the current through resistor e. Express your answer with the appropriate units. I, = Value Units Figure Submit Request Anewer 1 of 1 Part F ww Calculate the current through resistor t. R Express your answer with the appropriate units. A ww HA ? R. It = Value Units Submit Request Answer