Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
Please explain the process. Sometimes my answers come back through this service accuracy is priceless, and overly appreciated and even paid for. You Guys ROCK! Thank You Bartleby and Staff!
![### Calculus Problem: Computing Curl of a Vector Field
#### Problem Statement:
Find the curl of \(\vec{F}(x, y, z) = \langle 2x, 3y, 5z \rangle\).
#### Answer Choices:
- ⭕ `< 2, 3, 5 >`
- ⭕ `10`
- ⭕ `depends on the point (x, y, z)`
- ⭘ `< 0, 0, 0 >`
#### Solution Explanation:
In vector calculus, the curl of a vector field \(\vec{F} = \langle P, Q, R \rangle\) is given by:
\[
\nabla \times \vec{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)
\]
For \(\vec{F}(x, y, z) = \langle 2x, 3y, 5z \rangle\):
- \(P = 2x\)
- \(Q = 3y\)
- \(R = 5z\)
Calculate the components of the curl:
- \(\frac{\partial R}{\partial y} = \frac{\partial (5z)}{\partial y} = 0\)
- \(\frac{\partial Q}{\partial z} = \frac{\partial (3y)}{\partial z} = 0\)
- \(\frac{\partial P}{\partial z} = \frac{\partial (2x)}{\partial z} = 0\)
- \(\frac{\partial R}{\partial x} = \frac{\partial (5z)}{\partial x} = 0\)
- \(\frac{\partial Q}{\partial x} = \frac{\partial (3y)}{\partial x} = 0\)
- \(\frac{\partial P}{\partial y} = \frac{\partial (2x)}{\partial y} = 0\)
Thus:
\[
\nabla \times \vec{F} = \langle 0 - 0, 0 -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e343f85-ac09-4dac-ae1f-fa90b444949b%2Fcb530f83-86c2-4c75-b872-0cf4b048c0fe%2F40e345f_processed.png&w=3840&q=75)
Transcribed Image Text:### Calculus Problem: Computing Curl of a Vector Field
#### Problem Statement:
Find the curl of \(\vec{F}(x, y, z) = \langle 2x, 3y, 5z \rangle\).
#### Answer Choices:
- ⭕ `< 2, 3, 5 >`
- ⭕ `10`
- ⭕ `depends on the point (x, y, z)`
- ⭘ `< 0, 0, 0 >`
#### Solution Explanation:
In vector calculus, the curl of a vector field \(\vec{F} = \langle P, Q, R \rangle\) is given by:
\[
\nabla \times \vec{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)
\]
For \(\vec{F}(x, y, z) = \langle 2x, 3y, 5z \rangle\):
- \(P = 2x\)
- \(Q = 3y\)
- \(R = 5z\)
Calculate the components of the curl:
- \(\frac{\partial R}{\partial y} = \frac{\partial (5z)}{\partial y} = 0\)
- \(\frac{\partial Q}{\partial z} = \frac{\partial (3y)}{\partial z} = 0\)
- \(\frac{\partial P}{\partial z} = \frac{\partial (2x)}{\partial z} = 0\)
- \(\frac{\partial R}{\partial x} = \frac{\partial (5z)}{\partial x} = 0\)
- \(\frac{\partial Q}{\partial x} = \frac{\partial (3y)}{\partial x} = 0\)
- \(\frac{\partial P}{\partial y} = \frac{\partial (2x)}{\partial y} = 0\)
Thus:
\[
\nabla \times \vec{F} = \langle 0 - 0, 0 -
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images

Recommended textbooks for you

Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning

Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON

Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON

Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning

Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON

Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON

Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman


Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning