Find the critical value(s) and rejection region(s) for the indicated t-test, level of significance a, and sample size n. Right-tailed test, a = 0.005, n= 19 Click the icon to view the t-distribution table. The critical value(s) is/are (Round to the nearest thousandth as needed. Use a comma to separate answers as needed.)
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- Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a 0.05 significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective? LOADING... Click the icon to view the data table of the poplar weights. No Treatment Fertilizer Irrigation Fertilizer and Irrigation 1.24 0.99 0.09 0.93 0.65 0.94 0.63 1.41 0.41 0.55 0.13 1.06 0.15 0.51 0.88 1.49 1.31 1.01 0.84 Determine the null and alternative hypotheses. H0: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 Exactly two of the population means are equal.Exactly two of the population means are equal. Not all of the population means are equal.Not all of the population means…DII Given below are the sample means for fifteen samples consisting of five data values each. Assume that the mean of the sample means is ten and the computed values for the UCL and LCL of the chart are 15 and 5, respectively. Below is the chart. Is this process in statistical control? Why or why not? Select the best answer choice. Sample 1 2 3 Mean 9 11 6 17+ 16- 15 14+ 13+ 12+ 11+ 10- 9. 8+ 7- 6 5 4. 3- 2- 1- R Submit Question $ F4 % -1 + O No, because there are eight consecutive points all above or all below the centerline. O No, because there is a point lying beyond the upper or lower control limit. O No, because there is a pattern, trend, or cycle that is obviously not random. O No, because more than one of the answer choices above are correct. O Yes, this process is within statistical control. 5 T 4 5 12 9 ▬▬ FS 6 7 8 11 7 8 6 6 Y H 49 9 10 12 16 F6 8 & 7 9 U 11 12 6 13 J 10 F7 11 13 14 15 12 11 7 8 12 PrtScn 13 FB K 15 9 UCL centerline LCL Home 16 Q F9 L ) End 0 F10 A PgUp ☎Explain how to find the critical values for a t-distribution. Click the icon to view the t-distribution table. Give the first step. Choose the correct answer below. O A. Identify the level of significance and the degrees of freedom, d.f. =n-1. 2 O B. Identify the level of significance 1- a and the degrees of freedom, d.f. = n. c. Identify the level of significance a and the degrees of freedom, d.f. = n-1. 1-a O D. Identify the level of significance and the degrees of freedom, d.f. = n. 2 Find the critical value(s) using the given t-distribution table in the row with the.correct degrees of freedom. column with a V sign. If the hypothesis test is left-tailed, use the "One tail, a" "Two tails, "Two tails, a" "One tail, 5
- Does Hypnotism Relieve Pain? The table shows the pain levels of patients before and after hypnotism. Pain level is measured on a cm scale. Assume that the two samples are randomly selected. At the 0.05 significance level, test the claim that the mean difference has increased after hypnotism.(Be sure to subtract in the same direction).Explain how to find the critical values for a t-distribution. LOADING... Click the icon to view the t-distribution table. Question content area bottom Part 1 Give the first step. Choose the correct answer below. A. Identify the level of significance 1−α and the degrees of freedom, d.f.=n. B. Identify the level of significance α and the degrees of freedom, d.f.=n−1. C. Identify the level of significance α2 and the degrees of freedom, d.f.=n−1. D. Identify the level of significance 1−α2 and the degrees of freedom, df=nAvailable below are amounts of arsenic in samples of brown rice from three different regions. The amounts are in micrograms of arsenic and all samples have the same serving size. Use a 0.05 significance level to test the claim that the three samples are from populations with the same mean. Do the amounts of arsenic appear to be different in the different regions? Given that the amounts of arsenic in the samples from region C have the highest mean, can we conclude that brown rice from region C poses the greatest health problem? view the data table of the arsenic amounts. Arsenic Amounts (micrograms) A 4.9 4.9 4.9 5.2 5.3 5.5 5.6 5.7 5.8 5.9 6.1 6.3 B 2.3 3.6 4.5 4.6 4.8 4.8 4.8 5.1 5.1 5.4 5.4 5.5 C 5.7 5.7 6.7 6.9 7.1 7.2 7.2 7.3 7.3 7.4 7.5 7.6 What are the hypotheses to test? H0: mu 1 equals mu 2 equals mu 3μ1=μ2=μ3 H1: At least one…
- Answer with explationExplain how to find the critical values for a t-distribution. Click the icon to view the t-distribution table. Give the first step. Choose the correct answer below. O A. Identify the level of significance 2 and the degrees of freedom, d.f. = n-1. O B. Identify the level of significance 1-a and the degrees of freedom, d.f. = n. c. Identify the level of significance a and the degrees of freedom, d.f. = n- 1. 1-a O D. Identify the level of significance and the degrees of freedom, d.f. n. Find the critical value(s) using the given t-distribution table in the row with the correct degrees of freedom. If the hypothesis test is left-tailed, use the "One tail, a" column with a negative sign. If the hypothesis test is right-tailed, use the "One tail, a" column with a positive sign. If the hypothesis test is two-tailed, use the "Two tails, a" column with a negative and a positive sign.SAT Writing scores are distributed in population with μ = 487 and o = 115. Describe the sampling distribution of sample mean (the shape, mean, and standard error) for n = 64. Normal; 487; 14.38 Normal; 487; 115 Normal; 487; 1.80 Uniform; 487; 115
- N To determine if their 1.50 inch steel handles are properly adjusted, Smith & Johnson Industries has decided to use an X-Chart which uses the range to estimate the variability in the sample. Answe Step 2 of 7: What is the Upper Control Limit? Round your answer to three decimal places. Table 1 2 Control Chart Select the Copy Table button to copy all values. To select an entire row or column, either click on the row or column header or use the Shift and arrow keys. To find the average of the selected cells, select the Average Values button. Copy Table Average Values The average of the selected cell(s) is 1.460. Copy Value 34 Period obs1 obs2 obs3 obs4 obs5 obs6 Sample Mean Sample Range 1.46 1.50 1.46 1.53 1.55 1.54 1.5067 1.54 1.45 1.49 1.53 1.46 1.52 1.4983 1.50 1.54 1.47 1.51 1.45 1.47 1.4900 1.49 1.52 1.53 1.47 1.50 1.53 1.5067 5 1.46 1.45 1.49 1.4850 6 1.51 1.51 1.52 1.5117 7 1.53 1.50 1.47 1.54 1.5050 8 1.50 1.5067 1.54 1.50 1.47 1.46 1.54 1.53 1.53 1.46 1.51 1.52 1.50 1.47 1.54…A: 96, 122, 132, 111, 130, 99, 126, 113, 134, 126, 143, 132, 125, 115 B: 2.98, 3.85, 4.44, 4.84, 3.50, 4.87, 4.06, 4.45, 3.87, 4.70, 4.31 Step 1 of 2 : For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.Find the standardized test statistic, z, to test the hypothesis that p, p,. Use a = 0.02. The sample statistics listed below are from independent samples. Round to three decimal places. Sample statistics: n, = 1000, x, = 250, and n, = 1200, X2 = 195 O A. 3.212 O B. 2.798 O C. 5.087 O D. 4.761 Click to select your answer. 02/16/21 ch 2.3 Homework (99+ 000000 eesitphotoc