Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a 0.05 significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective? LOADING... Click the icon to view the data table of the poplar weights. No Treatment Fertilizer Irrigation Fertilizer and Irrigation 1.24 0.99 0.09 0.93 0.65 0.94 0.63 1.41 0.41 0.55 0.13 1.06 0.15 0.51 0.88 1.49 1.31 1.01 0.84 Determine the null and alternative hypotheses. H0: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 Exactly two of the population means are equal.Exactly two of the population means are equal. Not all of the population means are equal.Not all of the population means are equal. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 H1: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 At least one of the four population means is different from the others.At least one of the four population means is different from the others. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 Exactly two of the population means are different from the others.Exactly two of the population means are different from the others. mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 Find the F test statistic. F=enter your response here (Round to four decimal places as needed.) Find the P-value using the F test statistic. P-value=enter your response here (Round to four decimal places as needed.) What is the conclusion for this hypothesis test? A. Fail to reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. B. Fail to reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. C. Reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. D. Reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. Is there a treatment that appears to be most effective?
Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a 0.05 significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective? LOADING... Click the icon to view the data table of the poplar weights. No Treatment Fertilizer Irrigation Fertilizer and Irrigation 1.24 0.99 0.09 0.93 0.65 0.94 0.63 1.41 0.41 0.55 0.13 1.06 0.15 0.51 0.88 1.49 1.31 1.01 0.84 Determine the null and alternative hypotheses. H0: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 Exactly two of the population means are equal.Exactly two of the population means are equal. Not all of the population means are equal.Not all of the population means are equal. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 H1: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 At least one of the four population means is different from the others.At least one of the four population means is different from the others. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 Exactly two of the population means are different from the others.Exactly two of the population means are different from the others. mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 Find the F test statistic. F=enter your response here (Round to four decimal places as needed.) Find the P-value using the F test statistic. P-value=enter your response here (Round to four decimal places as needed.) What is the conclusion for this hypothesis test? A. Fail to reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. B. Fail to reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. C. Reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. D. Reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. Is there a treatment that appears to be most effective?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a
mean weight. Is there a treatment that appears to be most effective?
0.05
significance level to test the claim that the four treatment categories yield poplar trees with the same LOADING...
No Treatment
|
Fertilizer
|
Irrigation
|
Fertilizer and Irrigation
|
|
---|---|---|---|---|
1.24
|
0.99
|
0.09
|
0.93
|
|
0.65
|
0.94
|
0.63
|
1.41
|
|
0.41
|
0.55
|
0.13
|
1.06
|
|
0.15
|
0.51
|
0.88
|
1.49
|
|
1.31
|
1.01
|
0.84
|
|
Determine the null and alternative hypotheses.
H0:
▼
mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4
Exactly two of the population means are equal.Exactly two of the population means are equal.
Not all of the population means are equal.Not all of the population means are equal.
At least two of the population means are equal.At least two of the population means are equal.
mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4
mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4
H1:
▼
mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4
At least one of the four population means is different from the others.At least one of the four population means is different from the others.
At least two of the population means are equal.At least two of the population means are equal.
mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4
Exactly two of the population means are different from the others.Exactly two of the population means are different from the others.
mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4
Find the F test statistic.
F=enter your response here
(Round to four decimal places as needed.)Find the P-value using the F test statistic.
P-value=enter your response here
(Round to four decimal places as needed.)What is the conclusion for this hypothesis test?
Fail to reject
H0.
There is
sufficient
evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.Fail to reject
H0.
There is
insufficient
evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.Reject
H0.
There is
sufficient
evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.Reject
H0.
There is
insufficient
evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.Is there a treatment that appears to be most effective?
The 'Fertilizer and Irrigation'
method seems to be most effective.B.
No one treatment
method seems to be most effective.The 'Irrigation' method seems to be most effective.
The 'No Treatment' method seems to be most effective.
The 'Fertilizer' method seems to be most effective.
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