Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a 0.05 significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective? LOADING... Click the icon to view the data table of the poplar weights. No Treatment Fertilizer Irrigation Fertilizer and Irrigation 1.24 0.99 0.09 0.93 0.65 0.94 0.63 1.41 0.41 0.55 0.13 1.06 0.15 0.51 0.88 1.49 1.31 1.01 0.84 Determine the null and alternative hypotheses. H0: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 Exactly two of the population means are equal.Exactly two of the population means are equal. Not all of the population means are equal.Not all of the population means are equal. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 H1: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 At least one of the four population means is different from the others.At least one of the four population means is different from the others. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 Exactly two of the population means are different from the others.Exactly two of the population means are different from the others. mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 Find the F test statistic. F=enter your response here (Round to four decimal places as needed.) Find the P-value using the F test statistic. P-value=enter your response here (Round to four decimal places as needed.) What is the conclusion for this hypothesis test? A. Fail to reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. B. Fail to reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. C. Reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. D. Reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. Is there a treatment that appears to be most effective?

Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a 0.05 significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective? LOADING... Click the icon to view the data table of the poplar weights. No Treatment Fertilizer Irrigation Fertilizer and Irrigation 1.24 0.99 0.09 0.93 0.65 0.94 0.63 1.41 0.41 0.55 0.13 1.06 0.15 0.51 0.88 1.49 1.31 1.01 0.84 Determine the null and alternative hypotheses. H0: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 Exactly two of the population means are equal.Exactly two of the population means are equal. Not all of the population means are equal.Not all of the population means are equal. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 H1: ▼ mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4 At least one of the four population means is different from the others.At least one of the four population means is different from the others. At least two of the population means are equal.At least two of the population means are equal. mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4 Exactly two of the population means are different from the others.Exactly two of the population means are different from the others. mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4 Find the F test statistic. F=enter your response here (Round to four decimal places as needed.) Find the P-value using the F test statistic. P-value=enter your response here (Round to four decimal places as needed.) What is the conclusion for this hypothesis test? A. Fail to reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. B. Fail to reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. C. Reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. D. Reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. Is there a treatment that appears to be most effective?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Weights (kg) of poplar trees were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Use a

0.05

significance level to test the claim that the four treatment categories yield poplar trees with the same mean weight. Is there a treatment that appears to be most effective?

Click the icon to view the data table of the poplar weights.

No Treatment	Fertilizer	Irrigation	Fertilizer and Irrigation
1.24	0.99	0.09	0.93
0.65	0.94	0.63	1.41
0.41	0.55	0.13	1.06
0.15	0.51	0.88	1.49
1.31	1.01	0.84

Determine the null and alternative hypotheses.

H0:

▼

mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4

Exactly two of the population means are equal.Exactly two of the population means are equal.

Not all of the population means are equal.Not all of the population means are equal.

At least two of the population means are equal.At least two of the population means are equal.

mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4

mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4

H1:

▼

mu 1 greater than mu 2 greater than mu 3 greater than mu 4μ1>μ2>μ3>μ4

At least one of the four population means is different from the others.At least one of the four population means is different from the others.

At least two of the population means are equal.At least two of the population means are equal.

mu 1 equals mu 2 equals mu 3 equals mu 4μ1=μ2=μ3=μ4

Exactly two of the population means are different from the others.Exactly two of the population means are different from the others.

mu 1 not equals mu 2 not equals mu 3 not equals mu 4μ1≠μ2≠μ3≠μ4

Find the F test statistic.

F=enter your response here

(Round to four decimal places as needed.)

Find the P-value using the F test statistic.

P-value=enter your response here

(Round to four decimal places as needed.)

What is the conclusion for this hypothesis test?

Fail to reject

H0.

There is

sufficient

evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.

Fail to reject

H0.

There is

insufficient

evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.

Reject

H0.

There is

sufficient

evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.

Reject

H0.

There is

insufficient

evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight.

Is there a treatment that appears to be most effective?

The 'Fertilizer and Irrigation'

method seems to be most effective.

No one treatment

method seems to be most effective.

The 'Irrigation' method seems to be most effective.

The 'No Treatment' method seems to be most effective.

The 'Fertilizer' method seems to be most effective.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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