Find the critical value F-value to test the hypothesis that the type of insecticide makes no difference in the mean number of strawberries per plant
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Four different types of insecticides are used on strawberry plants. The number of strawberries on each randomly selected plant is given below. Find the critical value F-value to test the hypothesis that the type of insecticide makes no difference in the mean number of strawberries per plant. Use α=0.01.
|
Insecticide 1 |
Insecticide 2 | Insecticide 3 | Insecticide 4 |
| 6 | 8 | 6 | 3 |
| 5 | 5 | 3 | 5 |
| 6 | 5 | 3 | 3 |
| 7 | 5 | 4 | 4 |
| 7 | 5 | 2 | 5 |
| 6 | 6 | 3 | 4 |
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- A consumer magazine wants to compare the lifetimes of ballpoint pens of three different types. The magazine takes a random sample of pens of each type in the following table. Brand 1 Brand 2 Brand 3 260 181 238 218 240 257 184 162 241 219 218 213 Test the claim that there is a difference in mean lifetime for the three brands of ballpoint pens, using α=0.01. Round you answer to 3 decimal places.Women are recommended to consume 1700 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 1784, 1677, 1583, 1984, 1910, 1737, 1522, 1574, 1853, 1546, 1707, 1866 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.)To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material. Manufacturer 1 2 3 25 34 15 31 32 14 29 37 18 27 33 17 a. Use these data to test whether the population mean times for mixing a batch of material differ for the three manufacturers. Use a = 0.05. Sum of squares, treatment = Sum of squares, error = Mean squares, treatment = mean squares, error = Calculate the value of the test statistic (to 2 decimals). The P-value is: Less than 0.01, between 0.01 and 0.025, between 0.025 and 0.05, between 0.05 and 0.10, greater than 0.10 What is your conclusion? b. At the a = 0.05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3. What conclusion can you draw after carrying out this test?
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