Find the center of mass of the system of particles of masses of 1, 2, 3, 4 units at (4,2), (0,0), (3,4) and (-2,5) respectively.
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Solve and show the proper solution.
Find the center of mass of the system of particles of masses of 1, 2, 3, 4 units at (4,2), (0,0), (3,4) and (-2,5) respectively.
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- C4B.1 Consider a system consisting of two point particles A and B separated by 25 cm. The distance between particle A and the system's center of mass is 5 cm. What is the mass of particle B compared to the mass of particle A? (Hint: Put the center of mass at the origin.)A bomb is initially at rest and located at the origin of the coordinate system (0,0). The bomb explodes breaking up into three fragments of different masses. A camera registers the positions of the fragments after the explosion, as shown in the figure with (x,y) coordinates as follows: m1:(-6,5), m2:(5,0) and m3:(-3,-2), In the figure, the grid Y marks are separated by 1 m in each direction. Gravity and air resistance are negligible. m2 m3 What is the mass ratio of fragments 1 and 3? m,/m3 = 2/5 m1/m3 = 6/2 m1/m3 = 2/6A stone is dropped at t = 0. A second stone, with 3 times the mass of the first, is dropped from the same point at t=130 ms. (a) How far below the release point is the center of mass of the two stones at t = 260 ms? (Neither stone has yet reached the ground.) (b) How fast is the center of mass of the two-stone system moving at that time? (a) Number (b) Number eTextbook and Media Units Units
- A stone is dropped at t = 0. A second stone, with 4 times the mass of the first, is dropped from the same point at t = 55 ms. (a) How far below the release point is the center of mass of the two stones at t = 500 ms? (Neither stone has yet reached the ground.) (b) How fast is the center of mass of the two-stone system moving at that time? (a) Number Units (b) Number i Units >Please don't provide handwritten solution.....A particle with mass mA = 3.00 kg is located at rA = (2.50 i + 3.50 j) m, and a second particle of mass m2B = 5.00 kg is located at rB = (1.50 i – 3.00 j) m. Find the location of the center of mass of the system relative to the point (1,1).
- What’s the center of mass for each situation?Problem 3: A particle with mass ma = 3.00 kg is located at ra = (2.50 i + 3.50 j) m, and a second particle of mass m2B = 5.00 kg is located at rB = (1.50 i - 3.00 j) m. Find the location of the center of mass of the system relative to the point (1,1).As seen in the image provided, a double-star system with stars of equal mass rotate in circular orbits around their mutual center of mass that is halfway between them. One of the stars (α) is bright. The other star (β) is its unseen dark companion. Our line of sight passes through the orbital plane such that once in every period, α approaches head-on, and once ever period it recedes directly away. The same is true for β. Suppose light always moves at speed c relative to the source that emits it (i.e., if v is the orbital speed of each star, light travels toward us at speed c + v from α when it is headed toward us, and at speed c - v when it is headed away from us, as depicted). Find a distance d (in terms of v, c, and the orbital period T) such that α would appear to be simultaneously to the left and right of the center of mass point.
- 52. The Center of Mass of Sulfur Dioxide Sulfur dioxide (SO₂) consists of two oxygen atoms (each of mass 16 u, where u is defined in Problem 40) and a single sulfur atom (of mass 32 u). The center-to-center distance between the sulfur atom and either of the oxygen atoms is 0.143 nm, and the angle formed by the three atoms is 120°, as shown in Figure 9-20. Find the x and y coordinates of the center of mass of this molecule. Oxygen 0.143 nm y 120° Oxygen 0.143 nm Sulfur A FIGURE 9-20 Problem 52 ITwo stars in a binary system orbit around their center of mass. The centers of the two stars are 6.96x10¹¹ m apart. The larger of the two stars has a mass of 4.46x10³0 kg, and its center is 1.86x10¹¹ m from the system's center of mass. What is the mass of the smaller star?A stone is dropped at t = 0. A second stone, with 3 times the mass of the first, is dropped from the same point at t = 54 ms. (a) How far below the release point is the center of mass of the two stones at t = 270 ms? (Neither stone has yet reached the ground.) (b) How fast is the center of mass of the two-stone system moving at that time? (a) Number Enter your answer for part (a) in accordance to the question statement Units Choose the answer for part (a) from the menu in accordance to the question statement This answer has no units° (degrees)mkgsm/sm/s^2NJWN/mkg·m/s or N·sN/m^2 or Pakg/m^3gm/s^3times (b) Number Enter your answer for part (b) in accordance to the question statement Units Choose the answer for part (b) from the menu in accordance to the question statement This answer has no units° (degrees)mkgsm/sm/s^2NJWN/mkg·m/s or N·sN/m^2 or…