A thin rod of length L and density 1(x) = 1o(1 –). A right circular cylinder of height h, radius R and density a) p(r) = Po(1 – ) b) p(z) = po(1 –) - h

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**Transcription for Educational Website:**

A thin rod of length \( L \) and density 

\[
\lambda(x) = \lambda_0 \left(1 - \frac{x^2}{L^2}\right).
\]

A right circular cylinder of height \( h \), radius \( R \), and density:

a) \(\rho(r) = \rho_0 \left(1 - \frac{r}{R}\right)\)

b) \(\rho(z) = \rho_0 \left(1 - \frac{z}{h}\right)\)

**Explanation:**

- **Equation for Rod Density (\(\lambda(x)\))**: The density of a thin rod varies along its length \( L \), represented by the function \(\lambda(x)\). It decreases quadratically from a maximum at the center towards the ends.

- **Cylindrical Density Profiles**:
  - **Radial Density (\(\rho(r)\))**: Density varies linearly with the radial distance \( r \), decreasing from the center of the cylinder towards the surface at radius \( R \).
  - **Axial Density (\(\rho(z)\))**: Density varies linearly along the height \( h \) of the cylinder, decreasing uniformly from one base to the other.
Transcribed Image Text:**Transcription for Educational Website:** A thin rod of length \( L \) and density \[ \lambda(x) = \lambda_0 \left(1 - \frac{x^2}{L^2}\right). \] A right circular cylinder of height \( h \), radius \( R \), and density: a) \(\rho(r) = \rho_0 \left(1 - \frac{r}{R}\right)\) b) \(\rho(z) = \rho_0 \left(1 - \frac{z}{h}\right)\) **Explanation:** - **Equation for Rod Density (\(\lambda(x)\))**: The density of a thin rod varies along its length \( L \), represented by the function \(\lambda(x)\). It decreases quadratically from a maximum at the center towards the ends. - **Cylindrical Density Profiles**: - **Radial Density (\(\rho(r)\))**: Density varies linearly with the radial distance \( r \), decreasing from the center of the cylinder towards the surface at radius \( R \). - **Axial Density (\(\rho(z)\))**: Density varies linearly along the height \( h \) of the cylinder, decreasing uniformly from one base to the other.
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Solution:

 

It is given that,

 

λ(x)=λ01-x2L2

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