Find the mass and center of mass of the lamina that occupies the region D and has the given density function p. D = {(x, y) | 1 < x < 7, 1 < y s 4}; p(x, y) = ky2 m 3D (x, y)

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**Problem Statement:**

Find the mass and center of mass of the lamina that occupies the region \( D \) and has the given density function \( \rho \).

Region \( D \) is defined as: 
\[ D = \{(x, y) \mid 1 \leq x \leq 7, 1 \leq y \leq 4\} \]

The density function is given by:
\[ \rho(x, y) = ky^2 \]

**Equations to Calculate:**

- **Mass (\( m \)):**
  \[ m = \int \int_{D} \rho(x, y) \, dA \]
  (The actual computation will involve evaluating the double integral over the defined region with the given density function.)

- **Center of Mass (\( \bar{x}, \bar{y} \)):**
  \[
  \left( \bar{x}, \bar{y} \right) = \left( \frac{1}{m} \int \int_{D} x \rho(x, y) \, dA, \frac{1}{m} \int \int_{D} y \rho(x, y) \, dA \right)
  \]
  (These equations represent the coordinates for the center of mass based on the calculated mass.)

**Steps to Solve:**

1. Compute the mass \( m \) by setting up and evaluating the double integral of the density function over the region \( D \).
2. Calculate the \( x \)-coordinate (\( \bar{x} \)) of the center of mass by finding the moment in the \( x \)-direction using integration.
3. Calculate the \( y \)-coordinate (\( \bar{y} \)) of the center of mass by finding the moment in the \( y \)-direction using integration.
4. Use these calculated values to find the center of mass coordinates \( \left( \bar{x}, \bar{y} \right) \).

This problem involves calculus and integration over a defined region with a variable density function, which is typical in physics for determining mass properties of objects.
Transcribed Image Text:**Problem Statement:** Find the mass and center of mass of the lamina that occupies the region \( D \) and has the given density function \( \rho \). Region \( D \) is defined as: \[ D = \{(x, y) \mid 1 \leq x \leq 7, 1 \leq y \leq 4\} \] The density function is given by: \[ \rho(x, y) = ky^2 \] **Equations to Calculate:** - **Mass (\( m \)):** \[ m = \int \int_{D} \rho(x, y) \, dA \] (The actual computation will involve evaluating the double integral over the defined region with the given density function.) - **Center of Mass (\( \bar{x}, \bar{y} \)):** \[ \left( \bar{x}, \bar{y} \right) = \left( \frac{1}{m} \int \int_{D} x \rho(x, y) \, dA, \frac{1}{m} \int \int_{D} y \rho(x, y) \, dA \right) \] (These equations represent the coordinates for the center of mass based on the calculated mass.) **Steps to Solve:** 1. Compute the mass \( m \) by setting up and evaluating the double integral of the density function over the region \( D \). 2. Calculate the \( x \)-coordinate (\( \bar{x} \)) of the center of mass by finding the moment in the \( x \)-direction using integration. 3. Calculate the \( y \)-coordinate (\( \bar{y} \)) of the center of mass by finding the moment in the \( y \)-direction using integration. 4. Use these calculated values to find the center of mass coordinates \( \left( \bar{x}, \bar{y} \right) \). This problem involves calculus and integration over a defined region with a variable density function, which is typical in physics for determining mass properties of objects.
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