Find the best critical region for testing H, :1= 2 ~ H, : 2 = 3 based on the sample drawn from a Poisson population.
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A: See the handwritten solution
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- What conditions are necessary in order to use the dependent samples t-test for the mean of the difference of two populations?a sample of 60 grade 9 student age was obtained to estimate the mean age of all grade 9 students. x = 15.3 years and the population variance is 16Three adhesives are being analysed for their impact on the bonding strength of paper in a pulp and paper mill. The adhesives are each randomly applied to four batches. The data is shown in Table 2. Here, the three treatments are the adhesives (p=3) and the number of replications for each treatment is 4 (r=4). Is there a difference among the adhesives in terms of the mean bonding strength? Test at the 5% significance level. Given F0.05,2,9 = 4.26 Adhesive Bonding strength (kg) type Adhesive 1 10.2 11.8 Adhesive 2 12.8 14.7 Adhesive 3 7.2 9.8 Table 2 Bonding strength data 9.6 13.3 8.7 12.4 15.4 9.2
- 9 of 14 (14 complete) HW Score: 84.52%, 11.83 of 14 Y5.4.33 Question Help The height of women ages 20-29 is normally distributed, with a mean of 63.9 inches. Assume o = 2.8 inches. Are you more likely to randomly select 1 woman with a height less than 64.5 inches or are you more likely to select a sample of 25 women with a mean height less than 64.5 inches? Explain. Click the icon to view page 1 of the standard normal table. Click the icon to view page 2 of the standard normal table. What is the probability of randomly selecting 1 woman with a height less than 64.5 inches? (Round to four decimal places as needed.) ces ary ns Enter your answer in the answer box and then click Check Answer. Check Answer Clear All 2 parts remaining e here to searchWhich are the steps involved in the construction of explanatory bivariate tables?(Please explain what I was doing wrong)
- The data in table is from a randomized block design represent blood pressure measurements from an experiment involving 4 age groups, each with 3 persons. The 3 persons within each age group were randomly assigned to drugs, A, B and C with one person per drug. This was done to keep the drug assignments balanced within age groups. Comparing the three drugs in manner that provides balance for or control for possible age effects. Consider the data given in table below and compute; a. Mean Square Due to Treatments (MSTR) b. Mean Square Due to Blocks (MSBL) Mean Square Due to Error (MSE) C. d. F-test Treatments Age Groups (Blocks) A B 1 70 72 2 76 84 3 82 86 4 90 92 Total 318 334 C Total Blocks 80 222 82 242 84 252 88 270 334 986Exercise 3 Given a normally distributed population with mean of 75 and variance 625, find: i. P(50 90) ii. Р(X < 60) iv. P(30 < X < 110)
