Find the area of this triangle. 65° 18 [?] square units Round to the nearest hundredth.
Find the area of this triangle. 65° 18 [?] square units Round to the nearest hundredth.
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter61: Areas Of Circles, Sectors, And Segments
Section: Chapter Questions
Problem 38A: Three pieces, each in the shape of a sector, are cut from the rectangular sheet of steel shown. How...
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Hey what’s the answer to this
![**Find the area of this triangle.**
The image contains a triangle with the following features:
- One side of the triangle is labeled as 18 units.
- Another side of the triangle is labeled as 8 units.
- The angle between these two sides is labeled as 65 degrees.
The instructions below the triangle are:
**? square units**
Round to the nearest hundredth.
Below this text, there is a text entry box followed by an "Enter" button. This is likely for inputting the calculated area.
To solve for the area of a triangle given two sides and the included angle, you can use the formula:
\[
\text{Area} = \frac{1}{2}ab\sin(C)
\]
where:
- \(a\) and \(b\) are the lengths of the sides (8 and 18 units respectively)
- \(C\) is the included angle (65 degrees)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88948349-7a3a-42b1-b43e-0f6310456bad%2F679ce1e9-d219-42c8-b139-a8423118c3f2%2F76dsqrp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Find the area of this triangle.**
The image contains a triangle with the following features:
- One side of the triangle is labeled as 18 units.
- Another side of the triangle is labeled as 8 units.
- The angle between these two sides is labeled as 65 degrees.
The instructions below the triangle are:
**? square units**
Round to the nearest hundredth.
Below this text, there is a text entry box followed by an "Enter" button. This is likely for inputting the calculated area.
To solve for the area of a triangle given two sides and the included angle, you can use the formula:
\[
\text{Area} = \frac{1}{2}ab\sin(C)
\]
where:
- \(a\) and \(b\) are the lengths of the sides (8 and 18 units respectively)
- \(C\) is the included angle (65 degrees)
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