Find the area of this triangle. 17° 6 13.5 [?] square units Round to the nearest hundredth. Enter
Find the area of this triangle. 17° 6 13.5 [?] square units Round to the nearest hundredth. Enter
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter62: Volumes Of Prisms And Cylinders
Section: Chapter Questions
Problem 38A: A copper casting is in the shape of a prism with an equilateral triangle base. The length of each...
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![**Find the Area of this Triangle**
To calculate the area of the given triangle, use the following information and steps:
### Given:
- One side length: 6 units
- One side length: 13.5 units
- Included angle between these two sides: 17°
### Diagram Description:
The diagram is a triangle with a base of 6 units on the bottom. The left angle at the base is labeled as 17°. The hypotenuse (longest side) measures 13.5 units.
### Formula:
To find the area of a triangle using two sides and the included angle, use the following formula:
\[ \text{Area} = \frac{1}{2}ab \sin(C) \]
where:
- \( a \) and \( b \) are the lengths of the two sides.
- \( C \) is the included angle between these sides.
- \( \sin \) is the sine function.
### Calculation:
Substitute the given values into the formula:
\[ \text{Area} = \frac{1}{2} \times 6 \times 13.5 \times \sin(17^\circ) \]
**Steps:**
1. Calculate the sine of 17 degrees.
2. Multiply the sine value by 6 and 13.5.
3. Divide the product by 2.
### Result:
Round your answer to the nearest hundredth.
\[ \text{Area} = \boxed{?} \text{ square units} \]
### Instructions:
- **Round to the nearest hundredth.**
- **Enter your answer in the box provided.**
\[ \_\_\_\_\_\_\_\_\_\_\_\_\_\_ [Enter] \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88948349-7a3a-42b1-b43e-0f6310456bad%2F884a18d7-d33b-4616-9b54-07d6480f4e62%2F2vp8ou_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Find the Area of this Triangle**
To calculate the area of the given triangle, use the following information and steps:
### Given:
- One side length: 6 units
- One side length: 13.5 units
- Included angle between these two sides: 17°
### Diagram Description:
The diagram is a triangle with a base of 6 units on the bottom. The left angle at the base is labeled as 17°. The hypotenuse (longest side) measures 13.5 units.
### Formula:
To find the area of a triangle using two sides and the included angle, use the following formula:
\[ \text{Area} = \frac{1}{2}ab \sin(C) \]
where:
- \( a \) and \( b \) are the lengths of the two sides.
- \( C \) is the included angle between these sides.
- \( \sin \) is the sine function.
### Calculation:
Substitute the given values into the formula:
\[ \text{Area} = \frac{1}{2} \times 6 \times 13.5 \times \sin(17^\circ) \]
**Steps:**
1. Calculate the sine of 17 degrees.
2. Multiply the sine value by 6 and 13.5.
3. Divide the product by 2.
### Result:
Round your answer to the nearest hundredth.
\[ \text{Area} = \boxed{?} \text{ square units} \]
### Instructions:
- **Round to the nearest hundredth.**
- **Enter your answer in the box provided.**
\[ \_\_\_\_\_\_\_\_\_\_\_\_\_\_ [Enter] \]
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