2. Solve the equation on the interval [0, 27). Hint: Set equal to zero, don't cancel! √3 cos x cscx = 2 cos x
2. Solve the equation on the interval [0, 27). Hint: Set equal to zero, don't cancel! √3 cos x cscx = 2 cos x
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 69E
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Help me solve this with a radical
![2. Solve the equation on the interval [0, 27).
Hint: Set equal to zero, don't cancel!
3. For parts (a) - (c), use f(x) = 2 cos²x + √3 cos x
2 cos x + 1 = 0
3 cos x csc x = 2 cos x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F681a1dd5-ea79-4df0-af09-f7e014c18f3f%2F7fc5895b-47b8-479f-9cef-40183010af40%2Fr6kklwp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Solve the equation on the interval [0, 27).
Hint: Set equal to zero, don't cancel!
3. For parts (a) - (c), use f(x) = 2 cos²x + √3 cos x
2 cos x + 1 = 0
3 cos x csc x = 2 cos x
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