Find P(A or B or C) for the given probabilities. P(A) = 0.31, P(B) = 0.22, P(C) = 0.12 P(A and B) = 0.11, P(A and C) = 0.03, P(B and C) = 0.05 P(A and B and C) = 0.01 P(A or B or C) =

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**Title: Calculating the Probability of Events A, B, or C**

**Objective:**

To find the probability of the occurrence of at least one of the events A, B, or C using the given probabilities.

**Given Probabilities:**

- \( P(A) = 0.31 \)
- \( P(B) = 0.22 \)
- \( P(C) = 0.12 \)
- \( P(A \text{ and } B) = 0.11 \)
- \( P(A \text{ and } C) = 0.03 \)
- \( P(B \text{ and } C) = 0.05 \)
- \( P(A \text{ and } B \text{ and } C) = 0.01 \)

**Task:**

Compute the probability \( P(A \text{ or } B \text{ or } C) \).

**Formula Used:**

To find \( P(A \text{ or } B \text{ or } C) \), use the formula for the union of three events:

\[
P(A \text{ or } B \text{ or } C) = P(A) + P(B) + P(C) - P(A \text{ and } B) - P(A \text{ and } C) - P(B \text{ and } C) + P(A \text{ and } B \text{ and } C)
\]

**Solution:**

Substitute the given values into the formula:

\[
P(A \text{ or } B \text{ or } C) = 0.31 + 0.22 + 0.12 - 0.11 - 0.03 - 0.05 + 0.01
\]

Calculate step-by-step:

1. Sum of individual probabilities: \( 0.31 + 0.22 + 0.12 = 0.65 \)
2. Sum of pairwise intersections: \( 0.11 + 0.03 + 0.05 = 0.19 \)
3. Adding the intersection of all three: \( 0.65 - 0.19 + 0.01 = 0.47 \)

**Conclusion:**

The probability \( P(A \text{ or } B \text{ or } C) \) is calculated to be 0.47. Input your
Transcribed Image Text:**Title: Calculating the Probability of Events A, B, or C** **Objective:** To find the probability of the occurrence of at least one of the events A, B, or C using the given probabilities. **Given Probabilities:** - \( P(A) = 0.31 \) - \( P(B) = 0.22 \) - \( P(C) = 0.12 \) - \( P(A \text{ and } B) = 0.11 \) - \( P(A \text{ and } C) = 0.03 \) - \( P(B \text{ and } C) = 0.05 \) - \( P(A \text{ and } B \text{ and } C) = 0.01 \) **Task:** Compute the probability \( P(A \text{ or } B \text{ or } C) \). **Formula Used:** To find \( P(A \text{ or } B \text{ or } C) \), use the formula for the union of three events: \[ P(A \text{ or } B \text{ or } C) = P(A) + P(B) + P(C) - P(A \text{ and } B) - P(A \text{ and } C) - P(B \text{ and } C) + P(A \text{ and } B \text{ and } C) \] **Solution:** Substitute the given values into the formula: \[ P(A \text{ or } B \text{ or } C) = 0.31 + 0.22 + 0.12 - 0.11 - 0.03 - 0.05 + 0.01 \] Calculate step-by-step: 1. Sum of individual probabilities: \( 0.31 + 0.22 + 0.12 = 0.65 \) 2. Sum of pairwise intersections: \( 0.11 + 0.03 + 0.05 = 0.19 \) 3. Adding the intersection of all three: \( 0.65 - 0.19 + 0.01 = 0.47 \) **Conclusion:** The probability \( P(A \text{ or } B \text{ or } C) \) is calculated to be 0.47. Input your
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