Find load flow Solution1.2 20Z12 = 0.01+jo.03 inZ₁4=0.02+0.04иа9.01+10.030.02+0.04 0.01+0.0358-1Vek 1.05100 MVAPe=230 MW150 MW w140 MW01012 +0.03580 M√ar723=0.01+0.03 90 mvareZ34 = 0.012+ 10.035

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Answered: Find load flow Solution 1.2 20 Z12 =…

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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Find load flow Solution 1.2 20 Z12 = 0.01+jo.03 in Z₁4=0.02+0.04 и а 9.01+10.03 0.02+0.04 0.01+0.03 58-1 Vek 1.05 100 MVA Pe=230 MW 150 MW w 140 MW 01012 +0.035 80 M√ar 723=0.01+0.03 90 mvare Z34 = 0.012+ 10.035