Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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### Electrical Circuit Analysis

In the given circuit diagram, we see a combination of series and parallel resistors with current sources. The components and their respective configurations are detailed below:

1. **Voltage Source (represented by the circle with a '+' and '-' sign):** This source is providing electrical energy to the circuit.

2. **Series Resistor and Current I1:**
   - There's an unknown current \( I_1 \) flowing through the first resistor connected directly to the voltage source.

3. **Parallel Resistors and Current Splitting:**
   - The circuit branches into two parallel paths after the first resistor:
     - The upper branch, indicating a current of 6 mA.
     - The lower branch, indicating a current of 2 mA.

#### Problem Statement

- **Objective:** Find the current \( I_1 \) entering the parallel combination.

#### Tips for Solving

- **Applying Kirchhoff's Current Law (KCL):** At the junction where the circuit splits into two branches, the total current entering the junction (\( I_1 \)) is equal to the sum of the currents leaving the junction.
  
    \[
    I_1 = I_{\text{upper branch}} + I_{\text{lower branch}}
    \]

- **Given Values:**
  - Current through the upper branch = 6 mA.
  - Current through the lower branch = 2 mA.

#### Solution

By adding the current in the upper and lower branches:

\[
I_1 = 6\ \text{mA} + 2\ \text{mA} = 8\ \text{mA}
\]

Hence, 
\[ I_1 = 8\ \text{mA} \]

This simple analysis teaches how to apply Kirchhoff's Current Law to determine unknown currents in a circuit.
Transcribed Image Text:### Electrical Circuit Analysis In the given circuit diagram, we see a combination of series and parallel resistors with current sources. The components and their respective configurations are detailed below: 1. **Voltage Source (represented by the circle with a '+' and '-' sign):** This source is providing electrical energy to the circuit. 2. **Series Resistor and Current I1:** - There's an unknown current \( I_1 \) flowing through the first resistor connected directly to the voltage source. 3. **Parallel Resistors and Current Splitting:** - The circuit branches into two parallel paths after the first resistor: - The upper branch, indicating a current of 6 mA. - The lower branch, indicating a current of 2 mA. #### Problem Statement - **Objective:** Find the current \( I_1 \) entering the parallel combination. #### Tips for Solving - **Applying Kirchhoff's Current Law (KCL):** At the junction where the circuit splits into two branches, the total current entering the junction (\( I_1 \)) is equal to the sum of the currents leaving the junction. \[ I_1 = I_{\text{upper branch}} + I_{\text{lower branch}} \] - **Given Values:** - Current through the upper branch = 6 mA. - Current through the lower branch = 2 mA. #### Solution By adding the current in the upper and lower branches: \[ I_1 = 6\ \text{mA} + 2\ \text{mA} = 8\ \text{mA} \] Hence, \[ I_1 = 8\ \text{mA} \] This simple analysis teaches how to apply Kirchhoff's Current Law to determine unknown currents in a circuit.
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