Find f. f"(x) = cos(x), (0) = 2, f'(0) = 8, f "(0) = 4 %3D %3D f(x) = A stone is dropped from the upper observation deck of a tower, 850 m above the ground. (Assume g = 9.8 m/s2.) %3D (a) Find the distance (in meters) of the stone above ground level at time t. h(t) = (b) How long does it take the stone to reach the ground? (Round your answer to two decimal places.) (c) With what velocity does it strike the ground? (Round your answer to one decimal place.) m/s (d) If the stone is thrown downward with a speed of 3 m/s, how long does it take to reach the ground? (Round your answer to two

Q: Find f. f"(x) = cos(x), f(0) = 3, f'(0) = 6, f"(0) = 4

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Q: Find f(x)

A: It is given that f'x=1+3x, f4=25.

Q: If you know that f(x) = f'(x) = f"(x) and that f(2) = 3 while f(6) = 3e* then: T. f''(x) dx %3D

A: We have to evaluate the integral ∫26xf''(x)dx. We have given that f(x) = f'(x) = f''(x) and f(2) = 3…

Q: 3. Find f. (a) f"(x) = x + 12x² %3D

A:

Q: 3. Find f(x) if f'(x) = sec²x - sinx and f(TT/4) = 1. %3D %3D

A: Given: f'(x) = sec2x -sinx  To find: The value of f(x)  and  fπ4.

Q: Given f''(x) = – 9 sin(3x) and f'(0) = – 4 and f(0) = 5. %3D %D Find f() =

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Q: Given that f"(x) = cos(x), f'(T/2) = 8 and f(T/2) = 6 find: || f'(x) = f(x) =

A:

Q: Find f. f"(x) = cos(x), f(0) = 6, f'(0) = 4, f"(0) = 9 f(x) =

A: We can find the value of f(x) as below.

Q: Find f. f"(x) = 8x3 + 5, f(1) = 2, f'(1) = 3 %3D %3D f(x)

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Q: K Given f(x) = 17x³ cos x, find f'(x). f'(x) =

A: The objective is to find the derivative of f(x).

Q: c If f" (x) = 18 cos 3x and f' (0) = f(5) = 1, find f(x).

A: The solution of the problem is given in the next step.

Q: 4 3 f(x) = arcsec %3D f'(x) =

A: First simplify the given function than use chain Rule of derivative.

Q: Find f(t) given that f"(t)=sin(x) + cos(x) - 10, f'(0)=10, and f(0)=20.  Please show steps. Thanks.

A:

Q: Consider the following function. f"(0) = sin(0) + cos(0) Find f' if f'(0) = 2. f'(0) = %3D Find f if…

A: We can find the answer as below.

Q: Given that f"(x) = cos(x), f'(T/2) = 8 and f(T/2) = 7, find: %3D f'(z) =O %3D f(2) =U

A:

Q: Find f. f(x) = f ''(x) = cos(x), f(0) = 4, f'(0) = 5, f "(0) = 7

A:

Q: Find f. f(x) = f"(x) = cos(x), f(0) = 9, f'(0): = = 8, f "(0) = 6

A: Given,  f'''(x)=cosx, f(0)=9, f'(0)=8, f''(0)=6

Q: Find f. f"(x) = -2 + 36x - 12x2, f(0) = 2, f'(0) = 18

A: Given, .Given,  f(0)=2, f'(0)=18.We know,

Q: -g(x) = x²sinx cosx . Find g'(x).

A: We will use the product rule of differentiation to find the derivative.

Q: Find f'(x) if f(x) = (x³ + 6x – 4)°. %3D

A:

Q: Find f'(x) and f'(c). Function Value of c x² – 4 f(x) = C = 1 %3D х — 8

A:

Q: Find f. f(x) = f"(x) = -2 + 18x - 12x², f(0) = 3, f'(0) = 12

A: Integration

Q: Fihd f if f"(±) = sin(z), f(0) = -1, f'(0) = -1, f"(0) = -4. %3D f(z) =| D

A: Given: f'''(x)=sin(x),  f(0)=-1,  f'(0)=-1,  f"(0)=-4

Q: Find f, f "' (x) = cos(x), f(0) = 4, f'(0) = 4 f'(0) = 9 f(x) =

A: Given: f'''x=cosx, f0=4, f'0=4 and f"0=9 To find: fx Solution: We have f'''x=cosx Integrating both…

Q: Find f. (x + 1) f'(x) = (1) = 3 %3D f(x) =

A:

Q: f(z) = cos(4r +5) %3D

A: we have to derivative  we know that  d(cos (ax+b) ) = -sin (ax+b) a                        = - a sin…

Q: f"(x) = -2 + 24x – 12x2, f(0) = 3, f'(0) = 18 %3D %3D

A:

Q: If f(x) = cos cos x – 7 tan x, then | f'(x) = f'(3)

A:

Q: If f(x) = 4 cos(7 ln(x)), find f'(x). %3D Find f'(3).

A: Explanation of the answer is as follows

Q: If f'(1) = 3e2 and f(0) = 2 then find f(1). %3D %3D

A: Given:     To determine: f(1)

Q: If f(x) = 2 cos(3 In(x)), find f'(æ). Find f'(1).

A: