Find f. f "'(x) = cos x, f(0) = 9, f '(0) = 1, f"(0) = 3 f(x) =

Q: Find f. f(x) = f '''(x) = cos(x), f(0) = 9, f'(0) = 1, f ''(0) = 9

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A: Topic - Differential equations We are given f''(x)=x3-12x ,f'(1)=0 ,f(1)=10 ∫xndx=xn+1n+1+C

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Q: First find f' and then find f. f"(x) = 10x³ + 2x? – 5x – 7, - f'(1) = –6, f(1) = -3. f'(x) = f(x) =

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A: We can make it easier for you

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