Find E at (5, 0, 0) due to charge distribution labeled A in Figure 4.23. Using Coulombs Law PL=2 mC/m A Figure 4.23 For Problem 4.6. 3 P₁ = 5 mC/m² -2 P₁ = 1 mC/m³

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Find E at (5, 0, 0) due to charge distribution labeled A in Figure 4.23.
Using Coulombs Law
PL=2 mC/m
Figure 4.23 For Problem 4.6.
3
C
P₁ = 5 mC/m²
x=-2
-P₂ = 1 mC/m³
Transcribed Image Text:Find E at (5, 0, 0) due to charge distribution labeled A in Figure 4.23. Using Coulombs Law PL=2 mC/m Figure 4.23 For Problem 4.6. 3 C P₁ = 5 mC/m² x=-2 -P₂ = 1 mC/m³
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