A hydrogen atom ¹H with 200 eV of kinetic energy has a head-on, perfectly elastic collision with a ¹2C atom at rest. ▼ Part A Afterward, what is the kinetic energy, in eV, of ¹H? Express your answer in electron volts. KIH = Submit Part B ——| ΑΣΦ Kfc = Request Answer Afterward, what is the kinetic energy, in eV, of ¹2C? Express your answer in electron volts. IT ΑΣΦΑ ← С eV eV

A hydrogen atom ¹H with 200 eV of kinetic energy has a head-on, perfectly elastic collision with a ¹2C atom at rest. ▼ Part A Afterward, what is the kinetic energy, in eV, of ¹H? Express your answer in electron volts. KIH = Submit Part B ——| ΑΣΦ Kfc = Request Answer Afterward, what is the kinetic energy, in eV, of ¹2C? Express your answer in electron volts. IT ΑΣΦΑ ← С eV eV

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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QUESTION 10 Which of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108 m/s. a. hc/1.89 b. 1.89 x h x c c. 1.89/hxc d. (1.51 + 3.4)/hc e. hc/3.4
5. Calculate the mean, RMS, and most probable speeds for: 1) hydrogen molecule at temperatures of 100 K, 1000 K and 10,000 K and 2) xenon atom at temperatures of l100 K, 1000 K and 10,000 K. Assume the velocity distribution is a Maxwell-Boltzmann distribution for both.
Which of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108 m/s. a. 1.89/hxc b. hc/1.89 c. 1.89 x h x c d. (1.51 + 3.4)/hc e. hc/3.4
QUESTION 13 Removing an electron from the metal requires 3.5 eV. The conversion between eV and J is: 1 eV = 1.6 x 10-19 J a) How many Joules is that? b) What is the velocity of the electron upon emission if the electron's mass is m-9.1*10-31 kg?
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b. | Compare the average positions of the electron for H and He*.
loclk lyimy moot Sontace is Connect w ifh a p Cons tan Co mpressed a dis tance b 3.0 cn from ;h eỖwhhbr:uv. pos:týcn what issl done by sprwy foree 3.0 Cmg & Spr
2. Using the following form of the Maxwell-Boltzmann distribution function for speed, 32 mu? m f(v) = 4m exp 2rkT. 2kT show that (i) the root mean square velocity, Vrms is, 3kT Vrms = %3D m and (ii) the average velocity, vavy is, 8KT =
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15 Why we use cesium as a photo emissive surface ? Cesium has large number of electrons It has negative charge O It has low work function It emits electrons of same K.E