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Find an expression for the slope of the se- cant line through the points P(3, g(3)) and Q(x, g(x)) on the graph of y = g(x). 1. slope 2. slope 3. slope slope 5. slope = = = = g(3) - g(x) x-3 g(x) + g(3) 3-r g(x) = g(3) 3+x g(3) + g(x) 3+x g(x) = g(3) x-3

Find an expression for the slope of the se- cant line through the points P(3, g(3)) and Q(x, g(x)) on the graph of y = g(x). 1. slope 2. slope 3. slope slope 5. slope = = = = g(3) - g(x) x-3 g(x) + g(3) 3-r g(x) = g(3) 3+x g(3) + g(x) 3+x g(x) = g(3) x-3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find an expression for the slope of the se- cant line through the points P(3, g(3)) and Q(x, g(x)) on the graph of y = g(x). 2 1. slope 2. slope 3. slope 4. slope 5. slope = = g(3) - g(x) x-3 g(x) + g(3) 3 x g(x) = g(3) 3+x g(3) + g(x) 3+x g(x) = g(3) x-3
Transcribed Image Text:Find an expression for the slope of the se- cant line through the points P(3, g(3)) and Q(x, g(x)) on the graph of y = g(x). 2 1. slope 2. slope 3. slope 4. slope 5. slope = = g(3) - g(x) x-3 g(x) + g(3) 3 x g(x) = g(3) 3+x g(3) + g(x) 3+x g(x) = g(3) x-3
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