7. 2/3

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
icon
Related questions
Topic Video
Question
**Equation 7:**

\[ \frac{1}{x} = \frac{2}{3} - \frac{5}{6} \]

This equation involves finding the value of \( x \) by solving the given expression. On the left, the fraction \( \frac{1}{x} \) represents the reciprocal of \( x \). On the right, subtract the fractions \(\frac{5}{6}\) from \(\frac{2}{3}\). To perform the subtraction, you’ll need a common denominator, which in this case is 6.

**Steps for Solution:**

1. Convert \(\frac{2}{3}\) to a fraction with a denominator of 6:

   \[ \frac{2}{3} = \frac{4}{6} \]

2. Perform the subtraction:

   \[ \frac{4}{6} - \frac{5}{6} = \frac{-1}{6} \]

3. The equation now looks like: 

   \[ \frac{1}{x} = \frac{-1}{6} \]

4. Solve for \( x \) by taking the reciprocal:

   \[ x = -6 \]

Thus, the solution to the equation is \( x = -6 \).
Transcribed Image Text:**Equation 7:** \[ \frac{1}{x} = \frac{2}{3} - \frac{5}{6} \] This equation involves finding the value of \( x \) by solving the given expression. On the left, the fraction \( \frac{1}{x} \) represents the reciprocal of \( x \). On the right, subtract the fractions \(\frac{5}{6}\) from \(\frac{2}{3}\). To perform the subtraction, you’ll need a common denominator, which in this case is 6. **Steps for Solution:** 1. Convert \(\frac{2}{3}\) to a fraction with a denominator of 6: \[ \frac{2}{3} = \frac{4}{6} \] 2. Perform the subtraction: \[ \frac{4}{6} - \frac{5}{6} = \frac{-1}{6} \] 3. The equation now looks like: \[ \frac{1}{x} = \frac{-1}{6} \] 4. Solve for \( x \) by taking the reciprocal: \[ x = -6 \] Thus, the solution to the equation is \( x = -6 \).
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Discrete Probability Distributions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON
Contemporary Abstract Algebra
Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON
Introduction to Linear Algebra, Fifth Edition
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press
College Algebra (Collegiate Math)
College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education