Find AH° for BaCO3(s) --> BaO(s) + CO2(g) given 2 Ba(s) + O2(g) --> 2 BaO(s).. .AH° = -1107.0 kJ %D Ba(s) + CO2(g) + 1/2 O2(g) --> BaCO3(s)..AH° = -822.5 kJ %3D -1376.0 kJ -284.5 kJ -1929.5 kJ 269.0 kJ 537.0 kJ

Chemistry by OpenStax (2015-05-04)
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Find AH° for BaCO3(s) --> BaO(s) + CO2(g) given
2 Ba(s) + O2(g) --> 2 BaO(s)..
.AH° = -1107.0 kJ
%D
Ba(s) + CO2(g) + 1/2 O2(g) --> BaCO3(s)..AH° = -822.5 kJ
%3D
-1376.0 kJ
-284.5 kJ
-1929.5 kJ
269.0 kJ
537.0 kJ
Transcribed Image Text:Find AH° for BaCO3(s) --> BaO(s) + CO2(g) given 2 Ba(s) + O2(g) --> 2 BaO(s).. .AH° = -1107.0 kJ %D Ba(s) + CO2(g) + 1/2 O2(g) --> BaCO3(s)..AH° = -822.5 kJ %3D -1376.0 kJ -284.5 kJ -1929.5 kJ 269.0 kJ 537.0 kJ
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