Calculate the DH°rxn for the following reaction SiO₂(s) + 4HCI(g) ® SiCl4(g) + 2H₂O(g) Given that DH f [SiO₂(s)] = -910.9 kJ/mol; = -657.0 kJ/mol; DH°ƒ [SiCl4(9)] DH°f [HCI(g)] = -92.3 kJ/mol; DH°f [H₂O (9)] = -241.8 kJ/mol; Express your answer in decimal notation rounded to four significant figures.
Calculate the DH°rxn for the following reaction SiO₂(s) + 4HCI(g) ® SiCl4(g) + 2H₂O(g) Given that DH f [SiO₂(s)] = -910.9 kJ/mol; = -657.0 kJ/mol; DH°ƒ [SiCl4(9)] DH°f [HCI(g)] = -92.3 kJ/mol; DH°f [H₂O (9)] = -241.8 kJ/mol; Express your answer in decimal notation rounded to four significant figures.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![### Calculating the Standard Enthalpy Change (ΔH°_rxn) for a Chemical Reaction
In this learning module, we will calculate the standard enthalpy change (ΔH°_rxn) for the following chemical reaction:
\[ \text{SiO}_2(s) + 4\text{HCl}(g) \rightarrow \text{SiCl}_4(g) + 2\text{H}_2\text{O}(g) \]
To begin, let's look at the given standard enthalpy of formation (ΔH°_f) values for the reactants and products involved in the reaction:
- \( \Delta H^\circ_\text{f} [\text{SiO}_2(s)] = -910.9 \text{ kJ/mol} \)
- \( \Delta H^\circ_\text{f} [\text{SiCl}_4(g)] = -657.0 \text{ kJ/mol} \)
- \( \Delta H^\circ_\text{f} [\text{HCl}(g)] = -92.3 \text{ kJ/mol} \)
- \( \Delta H^\circ_\text{f} [\text{H}_2\text{O}(g)] = -241.8 \text{ kJ/mol} \)
#### Calculation:
The standard enthalpy change of the reaction can be calculated using the formula:
\[ \Delta H^\circ_\text{rxn} = \sum (\Delta H^\circ_\text{f, products}) - \sum (\Delta H^\circ_\text{f, reactants}) \]
So, we need to sum up the enthalpies of formation for the products and subtract the sum of the enthalpies of formation for the reactants:
\[ \Delta H^\circ_\text{rxn} = [\Delta H^\circ_\text{f} (\text{SiCl}_4(g)) + 2 \cdot \Delta H^\circ_\text{f} (\text{H}_2\text{O}(g))] - [\Delta H^\circ_\text{f} (\text{SiO}_2(s)) + 4 \cdot \Delta H^\circ_\text{f} (\text{HCl}(g))] \]
Substitute the given values into the equation:
\[ \Delta H](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9413ee1b-018f-4e4f-9457-fb88f0adac84%2F937a5227-be69-49d6-a62a-fbb9c67e80fc%2Fgluwuzo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculating the Standard Enthalpy Change (ΔH°_rxn) for a Chemical Reaction
In this learning module, we will calculate the standard enthalpy change (ΔH°_rxn) for the following chemical reaction:
\[ \text{SiO}_2(s) + 4\text{HCl}(g) \rightarrow \text{SiCl}_4(g) + 2\text{H}_2\text{O}(g) \]
To begin, let's look at the given standard enthalpy of formation (ΔH°_f) values for the reactants and products involved in the reaction:
- \( \Delta H^\circ_\text{f} [\text{SiO}_2(s)] = -910.9 \text{ kJ/mol} \)
- \( \Delta H^\circ_\text{f} [\text{SiCl}_4(g)] = -657.0 \text{ kJ/mol} \)
- \( \Delta H^\circ_\text{f} [\text{HCl}(g)] = -92.3 \text{ kJ/mol} \)
- \( \Delta H^\circ_\text{f} [\text{H}_2\text{O}(g)] = -241.8 \text{ kJ/mol} \)
#### Calculation:
The standard enthalpy change of the reaction can be calculated using the formula:
\[ \Delta H^\circ_\text{rxn} = \sum (\Delta H^\circ_\text{f, products}) - \sum (\Delta H^\circ_\text{f, reactants}) \]
So, we need to sum up the enthalpies of formation for the products and subtract the sum of the enthalpies of formation for the reactants:
\[ \Delta H^\circ_\text{rxn} = [\Delta H^\circ_\text{f} (\text{SiCl}_4(g)) + 2 \cdot \Delta H^\circ_\text{f} (\text{H}_2\text{O}(g))] - [\Delta H^\circ_\text{f} (\text{SiO}_2(s)) + 4 \cdot \Delta H^\circ_\text{f} (\text{HCl}(g))] \]
Substitute the given values into the equation:
\[ \Delta H
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