Find a vector parametric equation r(t) for the linethrough the points P = (4, -3, 4) and Q = (3, -6, 2)for each of the given conditions on the parameter t.(a) If 7 (0)=(4, −3, 4) and 7(2) = (3, −6, 2), thenr(t) = <4- -3r(t) =(b) If 7(6)== Pr(t) = <7-t22P and 7(8)and= <4--1493t24-t>(c) If the points P and Q correspond to the parametervalues t = 0 and t = -4, respectively, then=3t3,4->-397(8) = Q, then3t121,6-321 ,10-t>

Given:- Find a vector parametric equation r⇀t for the line through the points P=4,-3,4 and Q=3,-6,2…

Answered: Find a vector parametric equation r(t)…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Solve the following equations show your solutions. 1. Given the line 2x = 5y + 9. Find its equation in intercept/s form. 2. Determine the divergence of the vector: V = i(x^2)y + j(-xy) + k(xyz) at coordinates (3, 2, 1). 3. If "n" is any positive integer, then (n - 1)(n - 2)(n - 3)...(3)(2)(1) = ?
16. Find both the vector equation and the parametric equations of the line through (-2,2,8) and (1, - 4,0), where t =0 corresponds to the first given point. The vector equation is (x,y,z) = + (1). Find the parametric equations of the line through (-2,2,8) in the direction from (-2,2,8) toward (1,-4,0). The parametric equations are x = (Use the answer from the previous step to find this answer.) y%3D (1) O t(3,-6,-8). O t(-6,3,-8). O t(-8,-6,3). O t(-8,3,-6). 17. If possible, find the absolute maximum and minimum values of the following function on the region R. f(x,y) = 5 e-X-Y; R={(x,y): x20, y2 0} Determine the absolute maximum value of f(x,y) on R. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The absolute maximum value of f on R is O B. The function f(x,y) has no absolute maximum value on R. Determine the absolute minimum value of f(x,y) on R. Select the correct choice below and, if necessary, fill in the answer box to…
Express the given parametric equations of a line using bracket notation and also using i, j, k notation. (a) x = 6t, y = - 4 + 3t O (x, y) = (0, 4) +1 (6,3) ai + bj = -4j + t (6i + 3j) O (x, y) = (0, 4) + t (6, 3) ai + bj = 4j+ t (6i + 3j) O (x, y) = (0, 6) + (-4, 3) ai + bj = − 4j + t (6i + 3j) O(x, y) =(4,0) + t (3,6) ai + bj = −4i + t (3i + 6j) O (x, y) = (6,3)+1(0, - 4) ai + bj (6i + 3j) +t(-4j) (b)x= 4 + 6t,y=4+9t, z = 87t O (x, y, z) = (-4, 4, − 8) +1(-6, ai + bj + ck = 9,7) ( − 4i + 4j - 8 k) + t ( − 6i - 9j + 7k) O (x, y, z) = (4, ai + bj + ck = 4, 8) + t (6, 9, - 7) (4i − 4j + 8 k) + t (6i + 9j – 7k) O (x, y, z) = (6,9, −7) +1(4, - 4,8) ai + bj + ck = (6i + 9j − 7k) + t(4i - 4j + 8k) O (x, y, z) = (-6, 9, 7) + 1 - 4, 4, 8) ai+bj + ck = ( – 6i – 9j + 7k) + t( − 4i + 4j − 8k) O (x, y, z) = (4, 4, 8) + t (6,9,7) ai + bj + ck = (4i +4j + 8 k) + t (6i + 9j + 7k)
Let L be a line which is parallel to the line L1 : 2x = 3y = 6z and intersects two lines L2 : x = z – 4 = 0_and L3 : y = z + 4 = 0. (a) Find the parametric equations of the line L. (b) Let L4 be a line with symmetric equations Y – 8 x + 12 = 2 -z. Find the equation of the plane containing the lines L and L4.
The equations of lines L₁ and L2 are -(1) + () and r - (-) + ² (1) +t2 r= · and p are parameters (scalars). respectively, where t (i) Show that contains the point (2,-1,-4) but L₂ does not pass through this point; (ii) Find the acute angle between L₂ and the line joining (1,-1,1) and (2,-1,-4).
(20 Ex3 Find Equation of plane poss through point (3,-, 2) and the vectus A=itj+k', B= 2i-it3k
Take the parametric equations of the lines [x/13 = y/3 = z/8] and [x-11/-10 = y-3/-4 = z-8/-7]; Find the scalar equation of the lines in the form of ax+by+cz+d=0 Show how to check that (13,3,8) fits the equation of the plane. Show how to check how (0,0,0) fits the equation of the plane. Show to to check that (1,-1,1) fits the equation of the plane.

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