1) How was the direction vector determined to be (1, 1, 1) if when solving for the tangent line at t = 0 we got the following vector (1, 1, 0) 2) How were the parametric equations determined: n = 1 + t 4 = t 2 = 0 where did the variable 'n' come from? where did the 4 come from? where did the 2 c

Q: find the parametric equations for the line segment from (-2,5) to (7,-1) your equation for x should…

A: Definition used -             Parametric equation of a line-             Parametric equation of…

Q: Let L be the line with parametric equations x-2-2t y-10-2t 2-8-21 Find the vector equation for a…

A:

Q: 4

A:

Q: 5. A line is defined by the parametric equations x = -2 – t, and y = 4+ 2t, te R (a) Does the point…

A:

Q: 1. A line L passes throught point (2,-1,5) that is parallel to line given by l(t) = (t, −1+t, 2).…

A:

Q: Find vectors u and v such that the parametric equation of the line y= mx + b can be expressed as…

A: Given that  equation of the line is  y= mx + b…