Finally look at Example 7.14. Use this example to guide you in solving the following problems. (5) A titration is setup so that NaOH is in a buret and 25.0 ml of HBr soln is in a flask. The NaOH has a known molarity of 0.250 M. At the end point 36.3 ml of NaOH has been added to the HBr soln. What is the molarity of the HBr? mi Vi , = Mz Vz (H Br) %3D (NAOH) m of HBr =D 0.363 M m(25.0uL) = (0.150 m) (36.3 wL) 0,250 x 36.3 m= 25 (6) A second titration is performed using the same 0.250 M NaOH in a buret. This time 25.0 ml of an H2S04 soln is titrated. At the endpoint 47.8 mL of NaOH has been added to the H2SO4 soln. What is the molarity of the H2S04?

Finally look at Example 7.14. Use this example to guide you in solving the following problems. (5) A titration is setup so that NaOH is in a buret and 25.0 ml of HBr soln is in a flask. The NaOH has a known molarity of 0.250 M. At the end point 36.3 ml of NaOH has been added to the HBr soln. What is the molarity of the HBr? mi Vi , = Mz Vz (H Br) %3D (NAOH) m of HBr =D 0.363 M m(25.0uL) = (0.150 m) (36.3 wL) 0,250 x 36.3 m= 25 (6) A second titration is performed using the same 0.250 M NaOH in a buret. This time 25.0 ml of an H2S04 soln is titrated. At the endpoint 47.8 mL of NaOH has been added to the H2SO4 soln. What is the molarity of the H2S04?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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