Fill up the below state table by converting the most right two digits of the number 88 72 18 to BCD code and use it for column A (i.e. 18 becomes 0001 1000 and fills column A), then use second most right two digits for column B and then the third most two digits for column C. Design using D flip flops. Use K-map and draw the circuit.

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This question is from an old final exam in digital design, and I have no idea how to approach or what the correct answer is.  The question is exactly as seen in the image.

Fill up the below state table by converting the most right two digits of the number 88 72 18 to
BCD code and use it for column A (i.e. 18 becomes 0001 1000 and fills column A), then use
second most right two digits for column B and then the third most two digits for column C. Design
using D flip flops. Use K-map and draw the circuit.
Present States
Input
Next states
A
B
C
X
A
B
C
0
0
0
0
0
0
1
0
0
1
0
1
0
1
1
0
1
0
0
1
1
0
1
1
1
1
0
0
1
1
1
0
Implement the yellow highlighted table using multiplexers considering the digits used
above (88 72 18).
For this question present states columns A, B, C will be inputs and next state A will be the
output.
Transcribed Image Text:Fill up the below state table by converting the most right two digits of the number 88 72 18 to BCD code and use it for column A (i.e. 18 becomes 0001 1000 and fills column A), then use second most right two digits for column B and then the third most two digits for column C. Design using D flip flops. Use K-map and draw the circuit. Present States Input Next states A B C X A B C 0 0 0 0 0 0 1 0 0 1 0 1 0 1 1 0 1 0 0 1 1 0 1 1 1 1 0 0 1 1 1 0 Implement the yellow highlighted table using multiplexers considering the digits used above (88 72 18). For this question present states columns A, B, C will be inputs and next state A will be the output.
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"Implement the yellow highlighted table using multiplexers considering the digits used above (88 72 18). For this question present states columns A, B, C will be inputs and next state A will be the output."

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