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Based on electric circuit shown in Figure 2. Determine whether the LED 1 and LED 2 is "ON" or "OFF" for V1 = 2V and V1 = 3.5V if for both LEDS are silicon LED. Explain the answer given. V1 OUT R1 ОРАMP 100kN V2 LED 1 LED 2 4Vdc R2 500kN Figure 2: Op-Amp circuit with LED

Based on electric circuit shown in Figure 2. Determine whether the LED 1 and LED 2 is "ON" or "OFF" for V1 = 2V and V1 = 3.5V if for both LEDS are silicon LED. Explain the answer given. V1 OUT R1 ОРАMP 100kN V2 LED 1 LED 2 4Vdc R2 500kN Figure 2: Op-Amp circuit with LED

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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### Op-Amp Circuit with LEDs: Analysis and Explanation **Title: Analyzing LED Status in an Operational Amplifier Circuit** **Introduction:** The image above shows an operational amplifier (op-amp) circuit with two LEDs, labeled LED 1 and LED 2. We will analyze whether the LEDs are "ON" or "OFF" for given input voltages V1 = 2V and V1 = 3.5V, assuming both LEDs are silicon-based. **Circuit Description:** In the provided circuit (Figure 2): - **V1** is the input voltage at the non-inverting terminal of the op-amp. - **V2** is the reference voltage at the inverting terminal of the op-amp, set to 4V DC. - **R1** has a resistance of 100kΩ. - **R2** has a resistance of 500kΩ. - The op-amp output drives two LEDs in parallel. **Diagram Details:** The diagram shows a series of components connected as follows: 1. **Power Sources:** - V1 (+) terminal is connected to the non-inverting input. - V2 (+4V) terminal is connected to the inverting input through R1 and R2 forming a voltage divider. 2. **Operational Amplifier:** - The op-amp (represented as a triangle) has its inputs connected to V1 and through a voltage divider from V2. - The output of the op-amp is directly connected to the cathode of LED 1 and LED 2. 3. **LEDs Configuration:** - LED 1 and LED 2 are depicted with anodes connected to ground (0V). - The output from the op-amp is connected to the cathodes of both LEDs. **Analyzing LED Status:** 1. **For V1 = 2V:** - The non-inverting input of the op-amp is at 2V. - The inverting input is set by the voltage divider formed by R1 and R2. Using the voltage divider rule: \[ V_{inverting} = V2 \cdot \left(\frac{R2}{R1 + R2}\right) = 4V \cdot \left(\frac{500kΩ}{100kΩ + 500kΩ}\right) =
Transcribed Image Text:### Op-Amp Circuit with LEDs: Analysis and Explanation **Title: Analyzing LED Status in an Operational Amplifier Circuit** **Introduction:** The image above shows an operational amplifier (op-amp) circuit with two LEDs, labeled LED 1 and LED 2. We will analyze whether the LEDs are "ON" or "OFF" for given input voltages V1 = 2V and V1 = 3.5V, assuming both LEDs are silicon-based. **Circuit Description:** In the provided circuit (Figure 2): - **V1** is the input voltage at the non-inverting terminal of the op-amp. - **V2** is the reference voltage at the inverting terminal of the op-amp, set to 4V DC. - **R1** has a resistance of 100kΩ. - **R2** has a resistance of 500kΩ. - The op-amp output drives two LEDs in parallel. **Diagram Details:** The diagram shows a series of components connected as follows: 1. **Power Sources:** - V1 (+) terminal is connected to the non-inverting input. - V2 (+4V) terminal is connected to the inverting input through R1 and R2 forming a voltage divider. 2. **Operational Amplifier:** - The op-amp (represented as a triangle) has its inputs connected to V1 and through a voltage divider from V2. - The output of the op-amp is directly connected to the cathode of LED 1 and LED 2. 3. **LEDs Configuration:** - LED 1 and LED 2 are depicted with anodes connected to ground (0V). - The output from the op-amp is connected to the cathodes of both LEDs. **Analyzing LED Status:** 1. **For V1 = 2V:** - The non-inverting input of the op-amp is at 2V. - The inverting input is set by the voltage divider formed by R1 and R2. Using the voltage divider rule: \[ V_{inverting} = V2 \cdot \left(\frac{R2}{R1 + R2}\right) = 4V \cdot \left(\frac{500kΩ}{100kΩ + 500kΩ}\right) =
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