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Example 3-8 A PMMC instrument with FSD= 100 HA and R. -1 kn is to be employed as an ac va meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I- 100 HA peak current la" 0.637 100 A 0.637 157 A L- Capplied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops - 2V, (for D, and D, or D, and D) applied peak voltage - 1.414Vm total eircuit resistance - R, + R. 1414V,m- 2V, R, + R. 1.414Vm -2V, (1414 x 100 V)-(2 x0.7 V) 157 A - I ko 890.7 kn

Example 3-8 A PMMC instrument with FSD= 100 HA and R. -1 kn is to be employed as an ac va meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I- 100 HA peak current la" 0.637 100 A 0.637 157 A L- Capplied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops - 2V, (for D, and D, or D, and D) applied peak voltage - 1.414Vm total eircuit resistance - R, + R. 1414V,m- 2V, R, + R. 1.414Vm -2V, (1414 x 100 V)-(2 x0.7 V) 157 A - I ko 890.7 kn

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you explain how it came to the final answer, first picture (a) and second picture (b)? 
And what is the used of voltmeter sensitivity in solving the value of the multiplier resistor in series with the meter resistor?

Example 3-8 A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt- meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I.- 100 HA 100 µA 0.637 - 157 HA peak current I. 0.637 (applied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops = 2V, (for D, and D. or Dz and D) applied peak voltage = 1.414Vm total circuit resistance - R, + R. 1.414Vm -2V, R, +R. 1.414V - 2V, --R. (1.414 x 100 V)- (2 x 0.7 V) 157 HA -i k0 = 890.7 kn
Transcribed Image Text:Example 3-8 A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt- meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I.- 100 HA 100 µA 0.637 - 157 HA peak current I. 0.637 (applied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops = 2V, (for D, and D. or Dz and D) applied peak voltage = 1.414Vm total circuit resistance - R, + R. 1.414Vm -2V, R, +R. 1.414V - 2V, --R. (1.414 x 100 V)- (2 x 0.7 V) 157 HA -i k0 = 890.7 kn
Example 3-8 A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt- meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I- 100 HA peak current I- L- 100 A 0.637 - 157 HA 0.637 (applied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops = 2V, (for D, and D. or Dz and D) applied peak voltage = 1.414Vm total circuit resistance - R, + R. 1.414Vm -2V, R, + R. 1.414Vm - 2V, R,- - R. (1.414 x 100 V)-(2x0.7 V) 157 A -i k0 = 890.7 kn
Transcribed Image Text:Example 3-8 A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt- meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I- 100 HA peak current I- L- 100 A 0.637 - 157 HA 0.637 (applied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops = 2V, (for D, and D. or Dz and D) applied peak voltage = 1.414Vm total circuit resistance - R, + R. 1.414Vm -2V, R, + R. 1.414Vm - 2V, R,- - R. (1.414 x 100 V)-(2x0.7 V) 157 A -i k0 = 890.7 kn
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