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Fill in the missing information: symbol Be 2- s²- 0 atom or ion? check all that apply O neutral atom O neutral atom O neutral atom Ocation O anion Ocation anion Ocation O anion number of number of protons electrons 0 0 ions 46 0 43

Fill in the missing information: symbol Be 2- s²- 0 atom or ion? check all that apply O neutral atom O neutral atom O neutral atom Ocation O anion Ocation anion Ocation O anion number of number of protons electrons 0 0 ions 46 0 43

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Counting protons and electrons in atoms and atomic ions Fill in the missing information: symbol Be 2- S atom or ion? check all that apply neutral atom neutral atom O neutral atom Ocation cation cation O anion O anion anion number of number of protons electrons 0 0 46 0 0 43
Transcribed Image Text:Counting protons and electrons in atoms and atomic ions Fill in the missing information: symbol Be 2- S atom or ion? check all that apply neutral atom neutral atom O neutral atom Ocation cation cation O anion O anion anion number of number of protons electrons 0 0 46 0 0 43
Expert Solution
Step 1: Introduction to the neutral atom, cation and anion

Neutral atoms are the species that have no positive or negative charge on them. 

For a neutral atom, number of protons = number of electrons 

Cations are the species having positive charge and anions are the species having negative charge.  

The number of protons is always equal to atomic number of atom/ion. 

The number of electrons can be calculated as : 

Number of a electrons in neutral atom = number of protons 

number of electrons in anion = number of protons in parent atom + (charge on anion) 

Number of electrons in cation = number of protons in parent atom - (charge on cation). 

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