Fill-in-the-Blank To indicate that a linked list is empty, you should set the pointer to its head to the value __________.
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Fill-in-the-Blank
To indicate that a linked list is empty, you should set the pointer to its head to the value __________.
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- Duplicate Set This function will receive a list of elements with duplicate elements. It should add all of the duplicate elements to a set and return the set containing the duplicate elements. A duplicate element is an element found more than one time in the specified list. The order of the set does not matter. Signature: public static HashSet<Object> duplicateSet(ArrayList<Object> list) Example: INPUT: [2, 4, 5, 3, 3, 5] OUTPUT: {5, 3}typedef struct node_t node_t; struct node_t { }; int32_t value; node_t* next; node_t* insert (node_t* list, int32_t v, int32_t* flag); 3) As you may have noticed from MT1, Howie is lazy. He wants you to write the interface for the following implementation of function copy_to_linked_list. He really appreciates your help! /* copy_to_linked_list int32_t copy_to_linked_list (int32_t a[], int32_t size, node_t** list_p) { int32_t flag, i; for (i = 0; i < size; ++i) { *list_p = insert (*list_p, a[i], &flag); if (-1== flag) return -1; } return 0;Use the following node definition for this problem.struct NodeInt32{int32_t value; NodeInt32* next;} Write a function which searches a non-empty linked list for a target value. Its exact signature should be: NodeInt32* find(NodeInt32* head, int32_t target); The function should return the first node whose value equals target. If the target is not found in the list, then the function should return NULL.
- Project 2: Singly-Linked List The purpose of this assignment is to assess your ability to: ▪Implement sequential search algorithms for linked list structures ▪Implement sequential abstract data types using linked data ▪Analyze and compare algorithms for efficiency using Big-O notation For this assignment, you will implement a singly-linked node class. Use your singly-linked node to implement a singly-linked list class that maintains its elements in ascending order. The SinglyLinkedList class is defined by the following data: ▪A node pointer to the front and the tail of the list Implement the following methods in your class: ▪A default constructor list<T> myList ▪A copy constructor list<T> myList(aList) ▪Access to first elementmyList.front() ▪Access to last elementmyList.back() ▪Insert value myList.insert(val) ▪Remove value at frontmyList.pop_front() ▪Remove value at tailmyList.pop_back() ▪Determine if emptymyList.empty() ▪Return # of elementsmyList.size() ▪Reverse order of…card_t * moveCardBack (card t *head); The moveCardBack function will take the card in front of the pile and place it in the back. In coding terms, you are taking the head of the linked list and moving it to the end. The function has one parameter which is the head of the linked list. After moving the card to the back, the function returns the new head of the linked list.Assume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); if(curNode!=NULL) curNode=curNode->getNext(); } A.32 B.43 C.19 D.18
- You have a sorted linked list. Fill in the missing code in the following function. SortedType::DeleteItem(Item Type item) // pointer delete //trailing pointer // traveling pointer void { NodePtr tempPtr; NodePtr predLoc; NodePtr location: bool found false; // Find item to delete: Put your code below //delete item: Put your code belowstruct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };C++ The List class represents a linked list of dynamically allocated elements. The list has only one member variable head which is a pointer that leads to the first element. See the following code for the destructor to List. ~ List () { for (int i = 0; i <size (); i ++) { pop_back (); } } What problems does the destructor have? Select one or more options: 1. There are no parameters for the destructor. 2. The return value from pop_back (if any) is nerver handled. 3. The destructor will create a stack overflow. 4. The destructor will create dangling pointers. 5.The destructor will create memory leaks. 6.The destructor will create undefined behavior (equivalent to zero pointer exception). 7.The condition must be: i <size () - 1 8. There is at least one problem with the destructor, but none of the above.
- 5 partition_list (head) This is a little like split_list() from the Short problem, except that, instead of splitting the list into two by cutting it into the middle, you will now build two lists to return, using alternate values. The first value in the input list should be returned at the head of the first new list; the second value should be the head of the second list. Keep on alternating from there, putting one new value on the first list, and one on the second. (But remember that the length of the input list might be odd.) Example Suppose you have the following input list: 10 - 13 -> -1 -> 1000 - 0 It should return the following two lists: 10 1 0 13 -> 1000@6 The Reference-based Linked Lists: Select all of the following statements that are true. options: As a singly linked list's node references both its predecessor and its successor, it is easily possible to traverse such a list in both directions. According to the terminology introduced in class, the head reference variable in a singly linked list object references the list's first node. According to the terminology introduced in class, in a doubly linked list, each node references both the head and tail node. In a double-ended singly linked list, the tail reference variable provides access to the entire list. In a circular linked list, the last node references the first node.Having trouble with creating the InsertAtEnd function in the ItemNode.h file below. " // TODO: Define InsertAtEnd() function that inserts a node // to the end of the linked list" Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts ------------------------------------------------------- main.cpp -------------------------------------------------------- #include "ItemNode.h" int main() { ItemNode *headNode; // Create intNode objects ItemNode *currNode; ItemNode *lastNode; string item; int i; int input; // Front of nodes list headNode = new ItemNode(); lastNode = headNode; cin >> input; for (i = 0; i < input; i++) { cin >> item;…