Fill-in-the-Blank __________ a node means adding it to a list, but not necessarily to the end.
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__________ a node means adding it to a list, but not necessarily to the end.
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- // FILL IN THE BLANKS (LINKED-LISTS CODE) (C++)#include<iostream>using namespace std; struct ________ {int data ;struct node *next; }; node *head = ________;node *createNode() { // allocate a memorynode __________;temp = new node ;return _______ ;} void insertNode(){node *temp, *traverse;int n;cout<< "Enter -1 to end "<<endl;cout<< "Enter the values to be added in list"<<endl;cin>>n; while(n!=-1){temp = createNode(); // allocate memorytemp->data = ________;temp->next = ________;if ( ___________ == NULL){head = _________;} else {traverse = ( );while (traverse->next != ________{traverse = traverse-> ___________;} traverse->next= temp;} cout<<"Enter the value to be added in the list"<<endl;cin>>n; }} void printlist(){node *traverse = head; // if head == NULLwhile (traverse != NULL) { cout<<traverse->data<<" ";traverse = traverse->next;}} int main(){int option; do{cout<<"\n =============== MAIN…struct node{ int a; struct node * nextptr; }; Write two functions. One for inserting new values to a link list that uses the given node structure. void insert(struct node **head, int value); Second function is called to count the number of even numbers in the link list. It returns an integer that represents the number of even numbers. int countEvenNumbers(struct node *head); Write a C program that reads a number of integers from the user and insert those integers into a link list (use insert function). Later pass the head pointer of this link list to a function called countEvenNumbers. This function counts and returns the number of even numbers in the list. The returned value will be printed on the screen. Note 1: Do not modify the function prototypes. Sample Input1: Sample Output1: 45 23 44 12 37 98 33 35 -1 3 Sample Input2: Sample Output2: 11 33 44 21 22 99 123 122 124 77 -1 4@6 The Reference-based Linked Lists: Select all of the following statements that are true. options: As a singly linked list's node references both its predecessor and its successor, it is easily possible to traverse such a list in both directions. According to the terminology introduced in class, the head reference variable in a singly linked list object references the list's first node. According to the terminology introduced in class, in a doubly linked list, each node references both the head and tail node. In a double-ended singly linked list, the tail reference variable provides access to the entire list. In a circular linked list, the last node references the first node.
- Functions that look at a linked list but do not modify it are referred to as______________• find_last(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the last element of the list which is equal to the second input; if it cannot be found, returns None instead. >> find_last(['a', 'b', 'b', 'a'], 'b') 2 >>> ind = find_last(['a', 'b', 'b', 'a'], 'c') >>> print(ind) NoneFill-in-the-Blank __________ a list means traveling through the list.
- Fill-in-the-Blank In a(n) __________ list, the last node has a pointer to the first node.struct remove_from_front_of_dll { // Function takes no parameters, removes the book at the front of a doubly // linked list, and returns nothing. void operator()(const Book& unused) { //// TO-DO (13) |||| // Write the lines of code to remove the book at the front of "my_dll", // // Remember, attempting to remove an element from an empty data structure is // a logic error. Include code to avoid that. ///// END-TO-DO (13) //// } std::list& my_dll; };find_last(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the last element of the list which is equal to the second input; if it cannot be found, returns None instead. >>> find_last(['a', 'b', 'b', 'a'], 'b') 2 >>> ind = find_last(['a', 'b', 'b', 'a'], 'c') >>> print(ind) None • find_first(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the first element of the list which is equal to the second input; if it cannot be found, returns None instead. >>> find_first(['a', 'b', 'b', 'a'], 'b') 1 >>> ind = find_first(['a', 'b', 'b', 'a'], 'c') >>> print(ind) None In python