Figure below shows a parallel-plate capacitor of plate area A = 12.5 cm2 and plate separation 2d = 7.12 mm. The left half of the gap is filled with material of dielectric constant κ1 = 21.0; the top of the right half is filled with material of dielectric constant κ2 = 32.0; the bottom of the right half is filled with material of dielectric constant κ3 = 68.0. What is the capacitance? The figure illustrates a parallel-plate capacitor with a total plate area \( A = 12.5 \, \text{cm}^2 \) and a plate separation of \( 2d = 7.12 \, \text{mm} \). The structure is divided into sections with different dielectric materials:- The left half of the gap is filled with a material having a dielectric constant \( \kappa_1 = 21.0 \).- The right half is divided horizontally into two sections: - The top section contains a material with a dielectric constant \( \kappa_2 = 32.0 \). - The bottom section contains a material with a dielectric constant \( \kappa_3 = 68.0 \).The schematic depicts these details:1. The capacitor is split vertically into two equal sections with area \( A/2 \).2. The left section is uniformly filled with the material \( \kappa_1 \).3. The right section is divided horizontally, equally, with the top half \( d \) having \( \kappa_2 \) and the bottom half \( d \) having \( \kappa_3 \).The task is to determine the capacitance of this complex configuration.

Answered: Image /qna-images/answer/4cc68b41-c180-4c73-981a-b726fdb782b3.jpgThe effective capacitance is,

Answered: Figure below shows a parallel-plate…

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Figure below shows a parallel-plate capacitor of plate area A = 12.5 cm2 and plate separation 2d = 7.12
mm. The left half of the gap is filled with material of dielectric constant κ1 = 21.0; the top of the right
half is filled with material of dielectric constant κ2 = 32.0; the bottom of the right half is filled with
material of dielectric constant κ3 = 68.0. What is the capacitance?

The figure illustrates a parallel-plate capacitor with a total plate area \( A = 12.5 \, \text{cm}^2 \) and a plate separation of \( 2d = 7.12 \, \text{mm} \). The structure is divided into sections with different dielectric materials:

- The left half of the gap is filled with a material having a dielectric constant \( \kappa_1 = 21.0 \).
- The right half is divided horizontally into two sections:
- The top section contains a material with a dielectric constant \( \kappa_2 = 32.0 \).
- The bottom section contains a material with a dielectric constant \( \kappa_3 = 68.0 \).

The schematic depicts these details:

1. The capacitor is split vertically into two equal sections with area \( A/2 \).
2. The left section is uniformly filled with the material \( \kappa_1 \).
3. The right section is divided horizontally, equally, with the top half \( d \) having \( \kappa_2 \) and the bottom half \( d \) having \( \kappa_3 \).

The task is to determine the capacitance of this complex configuration.

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