Consider the conducting plates shown in Figure. If V (x = 0) = a and V (x = (a+4) mm) = (b+e+2) V, determine: V(x=d) = b+c+2 %3D i. V, E, P and D in the dielectric region (&, = 2.5+a) between the plates. ii. The surface charge density of free charge p, on the plates, the bound surface charge density of polarization charge P, and bound volume charge density ppv V(x-0) = a

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Note: The value of a=0, b=5 and C=7.
Consider the conducting plates shown in Figure.
If V (x = 0) = a and V (x = (a+4) mm) = (b+c+2) V,
determine:
V(x=d) 3 b+c+2
i. V, E, P and D in the dielectric region
+
(6, = 2.5+a) between the plates.
ii. The surface charge density of free charge ps on the
plates, the bound surface charge density of polarization
charge pps and bound volume charge density Ppv
V(x=0) = a
Transcribed Image Text:Consider the conducting plates shown in Figure. If V (x = 0) = a and V (x = (a+4) mm) = (b+c+2) V, determine: V(x=d) 3 b+c+2 i. V, E, P and D in the dielectric region + (6, = 2.5+a) between the plates. ii. The surface charge density of free charge ps on the plates, the bound surface charge density of polarization charge pps and bound volume charge density Ppv V(x=0) = a
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