Figure (A) shows the overall system for filtering a continuous-time signal using a discrete- time filter. (Note that this is the same procedure we have always followed in this class!) Plots of Xe(jw) (the original signal in the frequency domain) and H(e) (the discrete-time filter) are shown in Figure (B). For this problem, assume that the sampling period, T, equals 0.05 seconds. Conversion to a sequence p(t) = S(t – nT) Conversion x[n] h[n] y[n] = to an xe(NT) H(e) ye(nT) impulse train = Xc(jw) 2 -30T 30T (A) (B) yp(t) T H(ejw) 1 ¨¨¨NA¨¨¨ -ㅠ-ㅠ ㅠㅠ (a) Sketch Xp(jw). Be sure to accurately label both axes! H(jw) ㅠ T ye(t)
Figure (A) shows the overall system for filtering a continuous-time signal using a discrete- time filter. (Note that this is the same procedure we have always followed in this class!) Plots of Xe(jw) (the original signal in the frequency domain) and H(e) (the discrete-time filter) are shown in Figure (B). For this problem, assume that the sampling period, T, equals 0.05 seconds. Conversion to a sequence p(t) = S(t – nT) Conversion x[n] h[n] y[n] = to an xe(NT) H(e) ye(nT) impulse train = Xc(jw) 2 -30T 30T (A) (B) yp(t) T H(ejw) 1 ¨¨¨NA¨¨¨ -ㅠ-ㅠ ㅠㅠ (a) Sketch Xp(jw). Be sure to accurately label both axes! H(jw) ㅠ T ye(t)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![Figure (A) shows the overall system for filtering a continuous-time signal using a discrete-
time filter. (Note that this is the same procedure we have always followed in this class!)
Plots of Xe(jw) (the original signal in the frequency domain) and H(e) (the discrete-time
filter) are shown in Figure (B). For this problem, assume that the sampling period, T, equals
0.05 seconds.
2c(t)
Xp (t)
Conversion
to a
sequence
p(t) = [∞∞ √(t – nT)
n=1x
Conversion
to an
x[n] =
h[n]y[n] =
xc(nT) H(ejw) ye(nT) impulse train
Xc (jw)
2
-30T
30π
(A)
(B)
-π
(a) Sketch X₂ (jw). Be sure to accurately label both axes!
H(ejw)
-1
T
Yp(t)
πT
2
T
ㅠ
-
FE
π
^¨*
ㅠ
H(jw)
FEIE
T
Ye(t)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b5d3f26-cda5-43e5-8223-bfa02258241c%2F3dada694-0c66-40c6-8ed7-6409d3330cf9%2Ffllrvu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Figure (A) shows the overall system for filtering a continuous-time signal using a discrete-
time filter. (Note that this is the same procedure we have always followed in this class!)
Plots of Xe(jw) (the original signal in the frequency domain) and H(e) (the discrete-time
filter) are shown in Figure (B). For this problem, assume that the sampling period, T, equals
0.05 seconds.
2c(t)
Xp (t)
Conversion
to a
sequence
p(t) = [∞∞ √(t – nT)
n=1x
Conversion
to an
x[n] =
h[n]y[n] =
xc(nT) H(ejw) ye(nT) impulse train
Xc (jw)
2
-30T
30π
(A)
(B)
-π
(a) Sketch X₂ (jw). Be sure to accurately label both axes!
H(ejw)
-1
T
Yp(t)
πT
2
T
ㅠ
-
FE
π
^¨*
ㅠ
H(jw)
FEIE
T
Ye(t)
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