Figure 2a shows a uniform beam subject to a linearly distributed load. The equation for the resulting elastic (-x3 + 2L²×³ – L*x). (see Figure 2b) The following parameters are given for your Wo curve is y = - computation: L = 600 cm, E = 50000 kN/cm², I = 30000 cm“, and wo = 2.5 kN/cm. Use bisection method to determine the point of maximum deflection. 120EIL Wo -L· (a) (x = L, y = 0) (x = 0, y = 0) %3D (Б) Figure 2

Structural Analysis
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Chapter2: Loads On Structures
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Figure 2a shows a uniform beam subject to a linearly distributed load. The equation for the resulting elastic
(-x3 + 2L²×³ – L*x). (see Figure 2b) The following parameters are given for your
Wo
curve is y = -
computation: L = 600 cm, E = 50000 kN/cm², I = 30000 cm“, and wo = 2.5 kN/cm. Use bisection method to
determine the point of maximum deflection.
120EIL
Wo
-L·
(a)
(x = L, y = 0)
(x = 0, y = 0)
%3D
(Б)
Figure 2
Transcribed Image Text:Figure 2a shows a uniform beam subject to a linearly distributed load. The equation for the resulting elastic (-x3 + 2L²×³ – L*x). (see Figure 2b) The following parameters are given for your Wo curve is y = - computation: L = 600 cm, E = 50000 kN/cm², I = 30000 cm“, and wo = 2.5 kN/cm. Use bisection method to determine the point of maximum deflection. 120EIL Wo -L· (a) (x = L, y = 0) (x = 0, y = 0) %3D (Б) Figure 2
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