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Figure 2 shows an RC high-pass filter e- 2 sin (cot) Figure 2 RC high pass filter C = 0.47 uF HH R-330 ohms + Vout 1. Write the transfer function for the RC high-pass filter of Figure 2. First write it in terms of joo (or s) and then write it as its magnitude and phase angle.

Figure 2 shows an RC high-pass filter e- 2 sin (cot) Figure 2 RC high pass filter C = 0.47 uF HH R-330 ohms + Vout 1. Write the transfer function for the RC high-pass filter of Figure 2. First write it in terms of joo (or s) and then write it as its magnitude and phase angle.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Figure 2 shows an RC high-pass filter e- 2 sin (cot) C = 0.47 uF HH Ос fc R-330 ohms + Figure 2 RC high pass filter 1. Write the transfer function for the RC high-pass filter of Figure 2. First write it in terms of joo (or s) and then write it as its magnitude and phase angle. Vout 2. Determine and record below the cutoff frequencies of the circuit of Figure 2. Calculated Calculated (using nominal values) (using actual values) Obtained from measurements Unit radians / sec hertz 3. Sketch the straight line approximations of the frequency responses for the RC high-pass filter on Graph 1 (see later). Figure 3 shows and RL high-pass filter.
Transcribed Image Text:Figure 2 shows an RC high-pass filter e- 2 sin (cot) C = 0.47 uF HH Ос fc R-330 ohms + Figure 2 RC high pass filter 1. Write the transfer function for the RC high-pass filter of Figure 2. First write it in terms of joo (or s) and then write it as its magnitude and phase angle. Vout 2. Determine and record below the cutoff frequencies of the circuit of Figure 2. Calculated Calculated (using nominal values) (using actual values) Obtained from measurements Unit radians / sec hertz 3. Sketch the straight line approximations of the frequency responses for the RC high-pass filter on Graph 1 (see later). Figure 3 shows and RL high-pass filter.
frequency is the frequency at which the amplitude of the output voltage is 70.7% (=1/√2) of the amplitude of the input high frequency signal. This frequency is also called half-power frequency or 3- dB frequency. Why? The cutoff frequencies for a RC high-pass filter are identical to the values for the low-pass filter and are given as follows: 1 1 @c T 00C ● RC 2π Similarly for an RL high-pass filter, the cutoff frequencies are: 1 R R T L 2π 2πL As in the low-pass filter, the frequency response of a high-pass filter circuit is given by two graphs: • Voltage gain in dB versus frequency Phase shift versus frequency. Voltage gain and phase shift for any frequency are determined by finding the transfer function of the circuit. Recall that the transfer function is the ratio of output voltage phasor to the input voltage phasor. = and and fe Transfer function = V. = out V 1 2+RC in
Transcribed Image Text:frequency is the frequency at which the amplitude of the output voltage is 70.7% (=1/√2) of the amplitude of the input high frequency signal. This frequency is also called half-power frequency or 3- dB frequency. Why? The cutoff frequencies for a RC high-pass filter are identical to the values for the low-pass filter and are given as follows: 1 1 @c T 00C ● RC 2π Similarly for an RL high-pass filter, the cutoff frequencies are: 1 R R T L 2π 2πL As in the low-pass filter, the frequency response of a high-pass filter circuit is given by two graphs: • Voltage gain in dB versus frequency Phase shift versus frequency. Voltage gain and phase shift for any frequency are determined by finding the transfer function of the circuit. Recall that the transfer function is the ratio of output voltage phasor to the input voltage phasor. = and and fe Transfer function = V. = out V 1 2+RC in
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