Answer the following with illustration and solutions.2. Design a basic wide-band, RC band stop filter with a lower cut-off frequency of 250 Hz and a higher cut-off frequency of 1.2kHz. Find its center frequency, bandwidth and Q of the circuit assuming the capacitor for both filter sections is 0.1 microfarad.Thia is the example that might help. Example: Band-pass Filter CircuitDesign a basic wide-band, RC band stop filter with a lowercut-off frequency of 200HZ and a higher cut-offfrequency of 800Hz. Find the value of the resistor forboth frequencies, its center frequency, bandwidth and Qof the circuit assuming the capacitor for both filtersections is 0.1uFFor resistor values of the filters:1= 7.95kNR, =2nf.C1RH =2nfµC¯ 2n(800HZ)(0.1µF)%3D2п (200H2) (0.1иF)= 1.99kNFor the center frequency:fr = fi × fu = /(200H2)(800H2) = 400HZFor the bandwidth:BW = fµ – f.BW = 800HZ – 200HZFor the quiescent point (operating point):frQ =400HZ= 0.67%3DBW600HZBW = 600HZ

Band Stop Filter-It is the filter which stops only the range of frequencies that is specified…

Answered: RC band stop filter

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Answer the following with illustration and solutions.

2. Design a basic wide-band, RC band stop filter with a lower cut-off frequency of 250 Hz and a higher cut-off frequency of 1.2kHz. Find its center frequency, bandwidth and Q of the circuit assuming the capacitor for both filter sections is 0.1 microfarad.

Thia is the example that might help.

Example: Band-pass Filter Circuit
Design a basic wide-band, RC band stop filter with a lower
cut-off frequency of 200HZ and a higher cut-off
frequency of 800Hz. Find the value of the resistor for
both frequencies, its center frequency, bandwidth and Q
of the circuit assuming the capacitor for both filter
sections is 0.1uF
For resistor values of the filters:
1
= 7.95kN
R, =
2nf.C
1
RH =
2nfµC¯ 2n(800HZ)(0.1µF)
%3D
2п (200H2) (0.1иF)
= 1.99kN
For the center frequency:
fr = fi × fu = /(200H2)(800H2) = 400HZ
For the bandwidth:
BW = fµ – f.
BW = 800HZ – 200HZ
For the quiescent point (operating point):
fr
Q =
400HZ
= 0.67
%3D
BW
600HZ
BW = 600HZ

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